All categories

3 years ago

Solve for k. 5 + 2k = 7

Mathematics

2 answers:

ryzh [129]3 years ago

7 0

So 5 + 2k = 7k

Hope this helps

igomit [66]3 years ago

6 0

Answer:

k = 1

Step-by-step explanation:

5 + 2k = 7

2k = 7 - 5

k = 2/2

k = 1

You might be interested in

How do I Simplify i^54

yanalaym [24]

Answer:

$i^{54}=-1$

Step-by-step explanation:

First, recall the 4 basic imaginary exponents:

$i^1=i \text{, }i^2=-1\text{, }i^3=-1\text{ and } i^4=1$

So, we want to find:

$i^{54}$

This is the same as:

$=i^{52}\cdot i^2$

52 is 4 times 13. Thus:

$=(i^4)^{13}\cdot i^2$

Since we know that i to the fourth is 1:

$=(1)^{13}\cdot i^2$

Simplify:

$=i^2$

And this equals:

$=-1$

So:

$i^{54}=-1$

6 0

2 years ago

True or false a translation is a certain type of Transformation

natima [27]

yes it is a transformation because we're either making the point on a graph go up or down

4 0

3 years ago

1. A number plus 7 is at most 4.

nasty-shy [4]

Answer:

-3

4 - 7 = -3.

-3 + 7 = 4.

They are in a fact family.

The answer is -3.

Hope it helps!

3 0

2 years ago

Read 2 more answers

What is the surface area in square inches of the prism

Lerok [7]

Answer: the answer is 25

Step-by-step explanation:

7 0

2 years ago

Where are the asymptotes for the following function located? f (x) = StartFraction 14 Over (x minus 5) (x + 1) EndFraction

m_a_m_a [10]

Answer:

2 vertical asymptotes occurring at x = 5 and x = -1

Step-by-step explanation:

given

$f(x) = \frac{14}{(x-5)(x+1)}$

recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)

Equating the denominator to zero,

(x-5)(x+1) = 0

(x-5) =0

x = 5 (first asymptote)

or (x+1) = 0

x = -1 (2nd asymptote)

6 0

3 years ago