Answer:
The ordered pairs that are presented are (7, 99.5) and (3, 51.5)
Step-by-step explanation:
We are given the cost function of the carnival rides as
which is a typical linear expression of the form 
where here 
, 
, 
and 
. To check if an ordered pair i.e. a point 
, is represented by the table we can simply plug in the equivalent 
value in the equation, and check if the result matches the 
value.
So, lets assume that all points are given correctly and they are as follow:
Now let us check each point with our function as follow:
<u>Point A</u>
So point A is part of the equation.
<u>Point B</u>
So point B is NOT part of the equation.
<u>Point C</u>
<u />
<u />
So point C is part of the equation.
<u>Point D</u>
<u />
<u />
So point D is NOT part of the equation.
Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Three heads.
- Event B: Fair coin.
The probability associated with 3 heads are:
out of 0.5(fair coin).- 1 out of 0.5(biased).
Hence:
The probability of 3 heads and the fair coin is:
Then, the conditional probability is:
0.1 = 10% probability that the chosen coin was the fair coin.
A similar problem is given at brainly.com/question/14398287
Answer:
The probability is 0.971032
Step-by-step explanation:
The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.
The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:
In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:
(eq. 1)
So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:
P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)
We can also calculated that as:
P(x ≥ 5) = 1 - P(x ≤ 4)
Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)
Then, if we calculate every probability using eq. 1, we get:
P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765
P(x ≤ 4) = 0.028968
Finally, P(x ≥ 5) is:
P(x ≥ 5) = 1 - 0.028968
P(x ≥ 5) = 0.971032
Answer:
y = 25
Step-by-step explanation:
Given y = kx and k = 5 then
y = 5x ← equation of variation
When x = 5 , then
y = 5 × 5 = 25
