All categories

2 years ago

Y varies directly as x and k = 5 Y=kxFind y when x = 5

Mathematics

1 answer:

SpyIntel [72]2 years ago

5 0

Answer:

y = 25

Step-by-step explanation:

Given y = kx and k = 5 then

y = 5x ← equation of variation

When x = 5 , then

y = 5 × 5 = 25

You might be interested in

Sara is playing a board game. The probability that Sara will score a point on her next turn is 1/2 . Which statement describes t

Allushta [10]

sara is unlikely to score a point on her next turn

8 0

3 years ago

Maggie is training to run a 6 mile race. Her training program has her increase her weekly long run each week. This week she ran

Korvikt [17]

Answer:

Maggie will run 5.85 miles next week.

Step-by-step explanation:

Given:

Maggie is training to run a 6 mile race.

This week Maggie ran = 4.5 miles

Also Given:

Next week she will run 1.3 times as far as she did this week.

We need to distance she will run next week.

Now we know Next week she will run 1.3 times as far as she did this week.

It means Distance to be run next week will be equal to 1.3 times distance she ran this week.

Framing in equation form we get;

distance she will run next week = $1.3\times 4.5 = 5.85 \ miles$

Hence Maggie will run 5.85 miles next week.

6 0

3 years ago

What are the next 3 numbers in this sequence? 1,1,2,4,7,13,24,44

Bogdan [553]

81,149, 274.... adding three numbers from the last would help you

like if you take 7 = 4 + 2 +1

or 13 = 7 + 4 +2

similarly 44+24+13 = 81
81+44 +24 = 149
149 + 81 +44 = 274

hope you get it!

6 0

3 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago

Please help. Attached as an image

Triss [41]

Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45

chegg

someone solved it on this

https://youtu.be/UGjXlMVdZvc

4 0

2 years ago

Y varies directly as x and k = 5 Y=kxFind y when x = 5​

Y varies directly as x and k = 5 Y=kxFind y when x = 5