Answer:
Yes, the bathroom has enough water and shampoo for all of them.
Step-by-step explanation:
70L+ 60S < 5600
Putting 8 into L and 7 into S, gives:
70(8) + 60(7) = 560 + 420 = 980
That is definitely less than 5600, so water is OK.
Now,
0.02L + 0.01S
Putting 8 into L and 7 into S, gives:
0.02(8) + 0.01(7) = 0.16 + 0.07 = 0.23
That's definitely less than 2.5 liters, so shampoo is OK as well.
Hence, bathroom has enough water and shampoo for them.
We are given with three values and is asked in the problem to determine the sum of the three values. Using a calculator, the significant figures should be equal to 5, the answer is equal to 99.318. One can also use manual addition to verify the answer
Answer: See explanation
Step-by-step explanation:
a. Marisa drives 112 miles in 1 hour and 45 minutes, which means her speed is 64 miles per hour.
Speed = Distance / Time
= 112 / 1 45/60
= 112 / 1 3/4
= 112 × 4/7
= 64 miles per hour.
TRUE
b . If 6 pens cost $7.74, then 7 pens cost $9.03.
Cost of one pen = $7.74/6 = $1.29
Cost of 7 pens = $1.29 × 7 = $9.03
TRUE
c. If Raymond drives at a speed of 57 miles per hour, then it takes him 4 hours and 10 minutes to drive 256.5 miles.
Speed = Distance / Time
Speed = 256.5 / 57 = 4.5 = 4 hours 30 minutes
FALSE
d. If 17 identical cans of soup cost $38.59, then 3 of the cans must cost $6.81.
Cost of one can = $38.59 / 17 = $2.27
Cost of 3 cans = $2.27 × 3 = $6.81
TRUE
e. Mr. Mayes buys two dozen eggs for $8.40, which means that he pays 70 cents per egg.
A dozen = 12
2 dozens = 12 × 2 = 24
Cost of one egg = $8.40 / 24 = 0.35 = 35 cents
FALSE
Answer:
yaaa
Step-by-step explanation:
Answer:
EF , HG , Parallel
Step-by-step explanation:
Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.
Also given that AB was parallel to DC.
Now we have to fill in the certain blanks.
Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.
Also HG is parallel to DC, EFGH is a translated image of ABCD.
Also we are given that AB is parallel to DC. Hence we have following results.
AB║DC
AB║EF
Hence CD║EF
also
CD ║HG
CD║EF
Hence we can come to conclusion that
EF║HG
Hence our answer will be
corresponding segments EF and HG are parallel to each other.
