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3 years ago

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Jessie estiments the weight of her cat to be 10 pounds the actual weight of the cat is 13.75 pounds fine the percent error

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer:

The percent error would be 27.27%

Step-by-step explanation:

percent error = \frac{measured - actual}{actual} x 100%

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A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the

VARVARA [1.3K]

N = first integer
n + 1 = second integer
n + 2 = third
n + 3 = fourth

the sum is 114 so:

n + (n + 1) + (n + 2) + (n + 3) = 114

solve:

4n + 6 = 114
4n = 108
n = 27

so 27 is your first.
27 + 1 is your second (remember n +1 n +2 and n +3)

so your first four integers are: 27 28 29 and 30

(I'll also help with one)

week one: x
week two: x + 5
week three: 2(x+5) or 2x + 10

week1 + 2 + 3 = 431

so its:

x + (x+5) + (2x + 10)
4x + 15 = 431
4x = 416
x = 104

its then:

week one: 104 sold
week two: 109 sold (x + 5)
<span>week three: 218 (2x + 10)
</span>

7 0

3 years ago

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Work out <br><br> a) 4 1/3 x 6<br><br> b) 2 3/5 x 3 1/3

Slav-nsk [51]

Answer:

a) 26

b) 26/3 = 8 2/3

Step-by-step explanation:

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2 years ago

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Ms. Potts washed 1/4 of her laundry. Her son washed 3/7 of it. Who washed most of the laundry? How much of the laundry still nee

LenaWriter [7]

Answer:

Son washed more
Remaining 9/28 of the laundry

Step-by-step explanation:

<u>Make denominators common to see the difference in fractions:</u>

1/4 = 7/28
3/7 = 12/28

Son washed more laundry as 12/28 > 7/28

<u>Together they washed:</u>

7/28 + 12/28 = 19/28 of the laundry

<u>Remaining part is:</u>

1 - 19/28 =
28/28 - 19/28 =
9/28 of the laundry

7 0

3 years ago

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a woman buys a pair of shoes at a sale.she pays $60,saving $15 on the regular price.The percentage discount on the shoe is

AleksandrR [38]

20% because 75 is the total price and 75 over 15 is 5 and 100 divided by 5 is 20

6 0

3 years ago

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago