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2 years ago

Solve the inequality: ||3x−4| −5| >1

Mathematics

1 answer:

e-lub [12.9K]2 years ago

5 0

Answer:

Hope this helps!

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I need help answering this question.

Darina [25.2K]

Her credits need to be AT LEAST EQUAL TO OR GREATER THAN 144 (credit hours) so we can eliminate choices B and D.

She already completed 4 semesters in which she receives 15 credit per semester.

This expression can be written as 4(15).

She needs to do a certain remaining hours of credit which can be represented by c and only c without any other coefficient.

So, the most reasonable choice here is A.

7 0

3 years ago

Read 2 more answers

Solve for r.<br><br> 3r − 2r =

alexandr402 [8]

The answer if i’m not wrong would be r 3-2 equals 1 which is r.

3 0

2 years ago

Help Pre-Calc

Alex73 [517]

Answer:

B) vertical stretch

Step-by-step explanation:

Given that the cost of manufacturing x refrigerators is given by the function $f(x)= 2x^2 + 6000$ .

Now it says that the cost doubles for the year 2011 owing to higher raw material prices. So that means cost function will change from f(x) to 2f(x).

Now we need to decide the type of transformation from f(x) to 2f(x).

Remember that when f(x) changes to a*f(x) where value of "a" is greater than 1 then it stretches the function vertically by factor of "a".

in 2f(x), we have a=2

So that means "B) vertical stretch" is the correct choice.

6 0

2 years ago

How many extraneous solutions does the equation below have?

aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.

The given equation consisting of variable , m is

$\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})$

None of the two solution

$m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2})$ , is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0

2 years ago

Read 2 more answers

Solve the equation g+4/g-2 = g-5/g-8

Rudiy27

The answer of the above equation value of g = 22/3

7 0

2 years ago