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MariettaO [177]
4 years ago
7

The table shows a simulation to predict how many cars will arrive at a car wash. Each event represents how many cars arrive duri

ng a ten-minute period.Use the six randomly generated numbers 18, 38, 87, 16, 56, and 5 to predict the number of people coming in during the lunch hour.
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
4 0

Answer:

The number of cars passing or the people arriving during lunch hour will be around 220

Step-by-step explanation:

First we find the for ten minutes period from given data:

Average Cars in 10 minutes = (18+38+87+16+56+5)/6

Average Cars minutes = 36.67

Now, for average cars in 1 hr, we must multiply this value by 6. As, 10 minutes multiplied by 6 equals 1 hr.

Average cars in an hour = 36.67*6

<u>Average Cars in an hour = 220</u>

Hence, the number of cars or people arriving during lunch hour will also be equal to average number of cars arriving during an hour.

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Yuki888 [10]

Answer:

1 year

Step-by-step explanation:

1. Convert 10% into a z-score, using a calculator or whateva

2. Z = -1.281551 ( you can find this by doing the following equation: (x - mean) / (standard deviation)

3. Hence -1.281551 = (x - 4) / 2 or, x = 1.436898, ( rounded to the nearest year ) = 1 year

7 0
3 years ago
What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y
Mumz [18]

Answer:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Step-by-step explanation:

The question is poorly formatted.

Given

\sqrt[3]{2y^3} * 7\sqrt{18y}

Required

Derive an equivalent expression

\sqrt[3]{2y^3} * 7\sqrt{18y}

Express 18 as 9 * 2

\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}

Split the expression as follows:

\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}

Take positive square root of 9

\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}

\sqrt[3]{2y^3} * 21 * \sqrt{2y}

21*\sqrt[3]{2y^3} *  \sqrt{2y}

The cube root can be rewritten to give:

21*\sqrt[3]{2}*\sqrt[3]{y^3} *  \sqrt{2y}

\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y

So, we have:

21*\sqrt[3]{2} * y *  \sqrt{2y}

Rewrite as:

21y *\sqrt[3]{2}  *  \sqrt{2y}

Split \sqrt{2y

21y *\sqrt[3]{2}  *  \sqrt{2} * \sqrt{y}

Collect Like Terms

21y*\sqrt{y} *\sqrt[3]{2}  *  \sqrt{2}

Represent in index form

21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}

Apply law of indices

21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }

21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}

21*y^{\frac{3}{2}} *2^{\frac{5}{6}}

21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Hence:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

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4 years ago
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Answer:

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