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MariettaO [177]
4 years ago
7

The table shows a simulation to predict how many cars will arrive at a car wash. Each event represents how many cars arrive duri

ng a ten-minute period.Use the six randomly generated numbers 18, 38, 87, 16, 56, and 5 to predict the number of people coming in during the lunch hour.
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
4 0

Answer:

The number of cars passing or the people arriving during lunch hour will be around 220

Step-by-step explanation:

First we find the for ten minutes period from given data:

Average Cars in 10 minutes = (18+38+87+16+56+5)/6

Average Cars minutes = 36.67

Now, for average cars in 1 hr, we must multiply this value by 6. As, 10 minutes multiplied by 6 equals 1 hr.

Average cars in an hour = 36.67*6

<u>Average Cars in an hour = 220</u>

Hence, the number of cars or people arriving during lunch hour will also be equal to average number of cars arriving during an hour.

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The ratio of two numbers is 3 to 5. Their sum is 136. Find the two numbers. how do I write it into an equation?
kotykmax [81]
3X + 5X = 136
8X = 136
X = 17 
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4 0
3 years ago
PLEASE HELP!
Degger [83]

Answer:

Perimeter = 21.58 units

Step-by-step explanation:

Perimeter of a polygon = Sum of measures of all sides of the polygon

Perimeter of the quadrilateral LEAP = PL + AE + EL + LP

                                                            = 4.47 + 4.47 + 6.32 + 6.32

                                                            = 21.58 units

[If the distances between two point are not given, use the formula to calculate the distance between two points (x_1, y_1) and (x_2,y_2)

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

7 0
3 years ago
Solve for x.<br> 9 - 2x = 4x - 9
postnew [5]

Answer: x = 3

Step-by-step explanation:

9 - 2x = 4x - 9

18 -2x = 4x

18 = 6x

x = 3

5 0
3 years ago
Read 2 more answers
Someone help me ASAP!!!
Mila [183]

Given : Anne buys 600 packets of mints.

Given : Of these 600 packets of mints, 34% are small packets and 40% are large packets.

:\implies  Total % of small and large packets is (34 + 40) = 74%

It means : The remaining percentage is of the medium packets of mints which were brought by Anne.

:\implies  % of medium packets brought by Anne : (100 - 74) = 26%

:\implies \textsf{Number of medium packets brought by Anne : $\left(\dfrac{26}{100} \times 600\right)$}

:\implies \textsf{Number of medium packets brought by Anne : $\left(26 \times 6\right)$ = 156}

Given : Ben buys 400 packets of mints.

\textsf{Given : Of these 400 packets of mints, $\dfrac{3}{10}$ are small and $\dfrac{1}{10}$ are large}

\implies \textsf{Total fraction of small and large packets brought by Ben :$\left(\dfrac{3}{10} + \dfrac{1}{10}\right)$}

It means : The remaining fraction is of the medium packets of mints which were brought by Ben.

\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{3}{10} - \dfrac{1}{10}\right)$}

\implies \textsf{Fraction of medium packets brought by Ben : $\left(1 - \dfrac{4}{10}\right)$ = $\dfrac{6}{10}$}

:\implies \textsf{Number of medium packets brought by Ben : $\left(\dfrac{6}{10} \times 400\right)$}

:\implies \textsf{Number of medium packets brought by Anne : $\left(6 \times 40\right)$ = 240}

Given : Chas buys 210 small packets of mints.

Given : Number of small packets : number of medium packets = 3 : 4

\implies \mathsf{\dfrac{210}{number \ of \ medium \ packets} = \dfrac{3}{4}}

\implies \mathsf{Number \ of \ medium \ packets = \left(210 \times \dfrac{4}{3}\right)}

\implies \textsf{Number of medium packets brought by Chas = 280}

Total number of medium packets of mints brought by these three shop keepers (Anne, Ben, Chas) are :

:\implies  (156 + 240 + 280)

:\implies  676

5 0
3 years ago
Find approximate area of the Shaded part of the circle. Use 3.14 for pi.
Ganezh [65]
Let the radius of the bigger circle,R = 6cm
Let the radius of the smaller circle, r = 4cm
Area of the shaded region= area of the bigger circle - area of the smaller circle
Area of the smaller circle = πr^2
3.14×4×4 = 3.14×16 = 50.24cm^2
Area of the larger circle = πR^2
3.14×6×6 = 3.14×36 = 113.04cm^2
Therefore area of the shaded region = 113.04 - 50.24 = 62.8cm^2
6 0
3 years ago
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