All categories

3 years ago

Instrument Panel

Mathematics

1 answer:

Elenna [48]3 years ago

5 0

Some of them are too blurry to see, sorry i’ll answer the ones i can see:

C: Seat belt reminder
R: Fuel gauge
E: Oil temperature gauge
G: Tachometer
H: High beam indicator
I: Speedometer
F and J: Turn signal indicators
W: Transmission shift indicator
Y: Oil pressure gauge
Z: Odometer
L: Cruise control
K: Battery voltage gauge
P: Airbag indicator

You might be interested in

Kerstin has a square tile. The perimeter of the tile is 32 inches. What is the length of the tile?

Troyanec [42]

If it is a square all sides are equal, so the perimeter is equal to 4 times the length of one side...

4s=32

s=8in

4 0

3 years ago

Read 2 more answers

Devon purchased a new car valued at $16,000 that depreciated continuously at a rate of 35%. Its current value is $2,000. The equ

irga5000 [103]

I hope the equation will be 2000=16000(1-r)^t because t is missing in the equation which we need to find.

Given rate: r= 35%= 0.35.

So, first step is to plug in 0.35 for r in the given formula to get the value of t.

Hence, the equation will be:

2000=16000(1-0.35)^t

2000=16000(0.65)^t (By subtraction)

2000/16000= 16000(0.65)^t /16000 (Dividing each sides by 16000)

0.125 = 0.65^t (By simplifying).

log 0.125 = log 0.65^t (Taking log each sides to isolate t).

log 0.125 = t log 0.65 (By applying the log property).

$\frac{log 0.125}{log 0.65} =t$ (Dividing each sides by log 0.65)

-0.903/-0.187 =t

t= 4.83

t= 5 ( Rounded to nearest integers)

So, Devon's car is 5 years old.

7 0

4 years ago

In the regular octagon shown below, which of the following is the minimum angle of rotation about center point C will carry the

Shalnov [3]

Answer: 4)90˚

Step-by-step explanation:

(90˚ is more towards the middle

5 0

3 years ago

Read 2 more answers

Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.

Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

and join the outside point with center of the circle, we

formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

angle between them in one triangle equal to the

corresponding sides and angles in the second triangle,

then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0

4 years ago

Which line appears to have the same slope as the equation x-y=4 and has a y-intercept that is 2 units above the y-intercept of t

mezya [45]

Answer:

Step-by-step explanation:

First, find the y-intercept form of the equation:

x - y = 4

x - x - y = 4 - x

-y = 4 - x

-y = -x + 4

-y/-1 = -x/-1 + 4/-1 (to get the y positive)

y = x - 4

The y-intercept is -4. This means that a y-intercept two units above 4 would be -2. Whichever line crosses the y axis at the value of -2 is the answer (line B)

hope this helps :)

8 0

3 years ago