The graph below shows the amount of time Misha spent outside over a 30-day period. How might the graph be considered misleading?

Mathematics

2 answers:

Sauron [17]3 years ago

4 0

The y-interval shows exponential increase rather than linear increase.

Nata [24]3 years ago

4 0

Answer:

d on edg

Step-by-step explanation:

You might be interested in

I NEED HELP ASAP<br> solve for u<br> 12.8=4u

pochemuha

Answer: u= 3.2

Step-by-step explanation:

divide both by 4

4 0

3 years ago

Read 2 more answers

Someone Please Help Me On This

luda_lava [24]

1) 18
2) 4
3) 27
4) 9
5) x=8
6) x=6

8 0

3 years ago

A proportional relationship is shown in the table below: what is the slope and what numbers do i graph. ty besties

dangina [55]

Answer:

The slope of the line is $m = \frac{3}{5}$ and the equation of the line is $y = \frac{3}{5}\cdot x$ .

Step-by-step explanation:

From table we understand that slope of the line is constant, that is, for each change of $x$ there is one and only change in $y$ , fulfilling the main characteristic of a line and we can determine the slope for every point of the line by means of the following expression:

$m = \frac{y_{f}-y_{o}}{x_{f}-x_{o}}$ (1)

Where:

$x_{o}, x_{f}$ - Initial and final x-coordinates of the line.

$y_{o}, y_{f}$ - Initial and final y-coordinates of the line.

If we know that $(x_{o}, y_{o}) = (0,0)$ and $(x_{f},y_{f}) = (8,4.8)$ , then the slope of the line is:

$m = \frac{4.8-0}{8-0}$

$m = \frac{3}{5}$

From graph we conclude that x-intercept of the line is $b = 0$ . Hence, the equation of the line is $y = \frac{3}{5}\cdot x$ and we proceed to plot the expression with the help of a graphing tool.