Answer:
the question doesn't make sense... where are you that you are doing HW problems? :/ this time of year ??
Step-by-step explanation:
Answer:
H: 0, 1, 2, 3, 4, 5
plumber 1: 20, 70, 110, 160, 210, 260
plumber 2: 0, 60, 120, 180, 240, 300
plumber 1: C = 50h + 20
plumber 2: C = 60h
Well for a rectangle, the area
A=Length x Width,
1764<span>=Length x Width,
Since </span><span>the width of the field is 13 m more than the length, the length will be equal to the with + 13,
L=W+13,
</span>1764<span>=LW
</span>1764=(W+13)(W)
W=36 meters
They want the perimeters, so add them up
2W+2L
=2(36)+2(49)
=170 meters
Equations with absolute value:

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:


Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Answer:
M
Step-by-step explanation: