The specific heat of metal is c = 3.433 J/g*⁰C.
<h3>Further explanation</h3>
Given
mass of metal = 68.6 g
t metal = 100 °C
mass water = 84 g
t water = 20 °C
final temperature = 52.1 °C
Required
The specific heat
Solution
Heat can be formulated :
Q = m.c.Δt
Q absorbed by water = Q released by metal
84 x 4.184 x (52.1-20)=68.6 x c x (100-52.1)
11281.738=3285.94 x c
c = 3.433 J/g*⁰C.
Answer:
Rate of reaction = 2.0 M/s
Explanation:
2H2O2(g) --> 2H2O(g) + O2(g)
Rate of formation of H2O = 2.0 M/s
Rate of reaction can be measured using multiple techiques and parameters like volume, pressure etc.
Among these techniques is the measurement of appearance of products.
This means we have;
Rate of reaction = Rate of appearance of product
Hence;
Rate of reaction = 2.0 M/s
Answer:
Filtration is the best method or seiving to put the drink in a cup while the seed falls on the seiver
Explanation:
