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3 years ago

Which describes bonding electrons in a polar covalent bond?

Chemistry

1 answer:

raketka [301]3 years ago

3 0

Answer:

I think the third one

Explanation:

i think

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What is an example of a colloid? A. Soda B.Fog C.Jewelry D.Silverware

Olegator [25]

Answer:

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silverware

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4 years ago

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Identify the process being described by each sentence.

lana [24]

1.melting
2.freezing
3.condensation
4. evaporation
5.sublimation

5 0

3 years ago

Aluminum metal reacts with bromine, a red-brown liquid with a noxious odor. The reaction is vigorous and produces aluminum bromi

GuDViN [60]

Answer: The mass of bromine reacted is 160.6 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium = 18.1 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium}=\frac{18.1g}{27g/mol}=0.670mol$

The chemical equation for the reaction of aluminium and bromide follows:

$2Al+3Br_2\rightarrow 2AlBr_3$

By Stoichiometry of the reaction:

2 moles of aluminium reacts with 3 moles of bromine gas

So, 0.670 moles of aluminium will react with = $\frac{3}{2}\times 0.670=1.005mol$ of bromine gas.

Now, calculating the mass of bromine gas, we use equation 1:

Moles of bromine gas = 1.005 moles

Molar mass of bromine gas = 159.81 g/mol

Putting values in equation 1, we get:

$1.005mol=\frac{\text{Mass of bromine}}{159.81g/mol}\\\\\text{Mass of bromine}=(1.005mol\times 159.81g/mol)=160.6g$

Hence, the mass of bromine reacted is 160.6 grams.

5 0

3 years ago

Calculate the molarity of 3.00 moles of KCL dissolved in 2.00L of solution.

skad [1K]

Answer:

1.5 Molar solution in KCl

Explanation:

Definition of molarity => moles of solute / Volume of solution in Liters

Given 3.00 moles of solute dissolved in 2Liters of solution

Molarity of [KCl] = 3.00 moles KCl / 2Liters solution = 1.5 Molar solution in KCl

8 0

3 years ago

If 7.0 mol of NO and 5.0 mol of O2 are reacted tegethor. The reaction generates 3.0 mol of NO2. What is the percent yield for th

Nata [24]

Answer:

The answer to your question is: 43 %

Explanation:

Data

NO = 7 mol

O2 = 5 mol

NO2 = 3 mol

percent yield = ?

Reaction

2NO(g) + O2(g) ⇒ 2NO2(g)

Proportion of reactants

From the reaction 2 moles of NO / 1 moles of O2 = 2

From the experiment 7 moles of NO / 5 moles of O2 = 1.4

Then, the limiting reactant is NO.

Rule of three

2 moles of NO -------------- 2 moles of NO2

7 moles of NO -------------- x

x = (7 x 2) / 2

x = 7 moles of NO2

% yield = experimental/ theoretical x 100

% yield = 3/7 x 100

% yield = 42.9 ≈ 43

8 0

3 years ago