Question

Given an integer n and an array a of length n, your task is to apply the following mutation to a:

Answer 1

Answer:

The program written in Java is as follows

import java.util.Scanner;

public class mutilate {

public static void main(String [] args) {

Scanner input = new Scanner(System.in);

int n;

System.out.print("Array Length: ");

n = input.nextInt();

while(n<1 || n > 103)  {

    System.out.print("Array Length: ");

n = input.nextInt();

}

int a []= new int [n];

int b []= new int [n];

System.out.print("Enter Elements of the Array: ");

for(int i =0;i<n;i++)  {

 a[i] = input.nextInt();

}

System.out.print("Output: ");

for(int i =0;i<n;i++)  {

 if(i == 0)   {

     b[i] = 0+a[i]+a[i+1];

 }

 else if(i == n-1)   {

     b[i] = a[i - 1]+a[i]+0;

 }

 else   {

 b[i] = a[i - 1]+a[i]+a[i+1];    

 }

 System.out.print(b[i]+" ");

}

}

}

Explanation:

This line allows the program accepts user input

Scanner input = new Scanner(System.in);

This line declares integer n

int n;

The next two line prompts user for length of the array and also accepts input

System.out.print("Array Length: ");

n = input.nextInt();

The following while iteration ensures that the user input is between 1 and 103

while(n<1 || n > 103)  {

    System.out.print("Array Length: ");

n = input.nextInt();

}

The next two lines declares array a and b

int a []= new int [n];

int b []= new int [n];

The next for iteration allows user enter values for array a

System.out.print("Enter Elements of the Array: ");

for(int i =0;i<n;i++)  {

 a[i] = input.nextInt();

}

The next for iteration calculates and prints the values for array b based on the instruction in the question

System.out.print("Output: ");

for(int i =0;i<n;i++)  {

 if(i == 0)   {

     b[i] = 0+a[i]+a[i+1];

 }

 else if(i == n-1)   {

     b[i] = a[i - 1]+a[i]+0;

 }

 else   {

 b[i] = a[i - 1]+a[i]+a[i+1];    

 }

 System.out.print(b[i]+" ");

}

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