Answer:
h = 8.588 m
Explanation:
Given:
Mass of hockey puck: m = 200 g = 0.2 K
g
Angle of incline: θ = 30º (with respect to horizontal)
Coefficient of static and kinetic friction between the puck and ramp:
μ
s = 0.4 and μk = 0.3
initial speed:
v = 3.5 m
/s
Let h be the vertical height reached by the puck, above the ground. This corresponds to a distance of
d = h
*sin 30º = 2
*h
along the incline. As the puck is moving, only kinetic friction comes into play as it climbs up the incline. Let N be the normal reaction exerted by the metal ramp on the ball. Then,
N = m*g
*cos θ = 0.2
*9.8
1*cos 30
º = 1.6991 N
Therefore, kinetic friction acting on the puck is:
F
k = μ
k
*N = 0.3
*1.6974 = 0.50974 N
From work energy theorem, the change in kinetic energy should equal the work done by friction and gravity. Therefore,
0.5* 0.2
*16² = 0.50974
*2h + 0.2*9.81*h
⇒ h = 8.588 m
Bending, twisting, or the overall age of the cable, or other stuff like that.
The answer is c. I just took it on apex n that’s what I got lol
Answer: TRUE
Explanation: Networking technology is the term used to describe the entire processes through which computer or mobile systems are linked up either through optic fibers,wireless systems in order to enhance effective communication across networks or regions.
OSI (open system interconnection), the earliest models partitions into seven layers and the OSI is known as model that creates partitioning a communication system classing them into abstraction layers.
Answer: The answer is d.
Explanation:
UDP is a transport protocol (Layer 4 of the OSI model) that has no mechanism to provide a reliable transport between the source process and the destination one, as TCP does.
Anyway, due to this feature, is specially suitable for real-time applications , like video or audio, provided that the user can accept some loss in the stream.
Several real-time protocols, like RTP for instance (used for videoconferencing) use UDP as transport protocol.
