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trapecia [35]
3 years ago
13

How to solve (3,2) and (5,6) and turn it into 2x-y=4

Mathematics
2 answers:
Bingel [31]3 years ago
7 0

You can start with the formula

... ∆y(x -x₁) -∆x(y -y₁) = 0

where ∆x = (x₂ -x₁) and ∆y = (y₂ -y₁). It does not matter which point you consider 1 or 2, but it is usually convenient to choose them so the differences are positive.

... (∆x, ∆y) = (5, 6) - (3, 2) = (2, 4)

For purposes of the above equation, it is convenient to divide these differences by any common factor they might have. Here, that factor is 2, so we can use

... (∆x, ∆y) = (1, 2) . . . . . . where (1, 2) = (2/2, 4/2)

Then, using ∆y=2, ∆x=1, x₁=3, y₁=2, the equation for the line becomes

... 2(x -3) - 1(y -2) = 0

... 2x -y -4 = 0 . . . . . . . simplified to general form

... 2x -y = 4 . . . . . . . . . add 4 to put in standard form.

_____

The equation used here is a variation of the 2-point form of the equation for a line. That equation is usually seen as

... y -y₁ = (y₂ -y₁)/(x₂ -x₁)·(x -x₁)

In the terms used above, it can be written as ...

...  y -y₁ = ∆y/∆x·(x -x₁)

Multiplying by ∆x and subtracting the left side, we see it as above:

... ∆y·(x -x₁) - ∆x·(y -y₁) = 0

Zolol [24]3 years ago
5 0
Find the slope between the 2 points and plug inotllto point slope form
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Find the probability of winning a lottery by selecting the correct six integers, where the order in which these inte
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The probability of winning a lottery by selecting the correct six integers, are

\begin{aligned}&(a) 1.68 \times 10^{-6} \\&(b) 5.13 \times 10^{-7} \\& (c) 1.91 \times 10^{-7} \\&(d)8.15 \times 10^{-8}\end{aligned}

<h3>What is binomial distribution?</h3>

The binomial distribution is a type of probability distribution that expresses the probability that, given a certain set of characteristics or assumptions, a value would take one of two distinct values.

Part (a); positive integers not exceeding 30.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other twenty-four.

\frac{\left(\begin{array}{c}6 \\6\end{array}\right)\left(\begin{array}{c}24 \\0\end{array}\right)}{\left(\begin{array}{c}30 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}30 \\6\end{array}\right)}=1.68 \times 10^{-6}

Part (b); positive integers not exceeding 36.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other thirty.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}30 \\0\end{array}\right)}{\left(\begin{array}{c}36 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}36 \\6\end{array}\right)}=5.13 \times 10^{-7}

Part (c); positive integers not exceeding 42.

To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the 36 other integers.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}36 \\0\end{array}\right)}{\left(\begin{array}{c}42 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}42 \\6\end{array}\right)}=1.91 \times 10^{-7}

Part (d); positive integers not exceeding 48.

To calculate the probability, use binomial coefficients. Choose six of the six accurate integers and none of the other 42.

\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}42 \\0\end{array}\right)}{\left(\begin{array}{c}48 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}48 \\6\end{array}\right)}=8.15 \times 10^{-8}

To know more about binomial probability, here

brainly.com/question/9325204

#SPJ4

The complete question is-

Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are selected does not matter, from the positive integers not exceeding a) 30. b) 36. c) 42. d) 48.

5 0
2 years ago
What is the value of f?<br><br> −18f−34−14f=11
Brrunno [24]
-18f - 34 - 14f = 11
-32f - 34 = 11
-32f = 45
f = -32/45
Simplify the fraction if needed!
Hope this helps, and please mark brainliest!

6 0
3 years ago
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