-10>-8-48x-2
-10>-10-48x
48x>-10+10
48x>0
x>0
So go to the negative 6 (-6) line and move up four(4).
AND your point will be at,
-2.
Answer:
Step 1: Simplify both sides of the equation.
Step-by-step explanation:
x+−13=13
From the point-slope formula, we have:
![y-y_0=m(x-x_0)](https://tex.z-dn.net/?f=y-y_0%3Dm%28x-x_0%29)
where m is the slope, (x_0,y_0) are known points.
In this case, we have the slope and two points, we can substitute in the formula to get:
![\begin{gathered} \text{if:} \\ (x,y)=(-6,-4) \\ \text{and} \\ (x_0,y_0)=(a,2) \\ \Rightarrow-4-2=\frac{2}{3}(-6-a) \\ \Rightarrow-6=-\frac{2\cdot6}{3}-\frac{2}{3}a \\ \Rightarrow-6=-4-\frac{2}{3}a \\ \Rightarrow-6+4=-\frac{2}{3}a \\ \Rightarrow-2=-\frac{2}{3}a\Rightarrow a=-\frac{2}{-\frac{2}{3}}=\frac{3\cdot2}{2}=\frac{6}{2}=3 \\ a=3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7Bif%3A%7D%20%5C%5C%20%28x%2Cy%29%3D%28-6%2C-4%29%20%5C%5C%20%5Ctext%7Band%7D%20%5C%5C%20%28x_0%2Cy_0%29%3D%28a%2C2%29%20%5C%5C%20%5CRightarrow-4-2%3D%5Cfrac%7B2%7D%7B3%7D%28-6-a%29%20%5C%5C%20%5CRightarrow-6%3D-%5Cfrac%7B2%5Ccdot6%7D%7B3%7D-%5Cfrac%7B2%7D%7B3%7Da%20%5C%5C%20%5CRightarrow-6%3D-4-%5Cfrac%7B2%7D%7B3%7Da%20%5C%5C%20%5CRightarrow-6%2B4%3D-%5Cfrac%7B2%7D%7B3%7Da%20%5C%5C%20%5CRightarrow-2%3D-%5Cfrac%7B2%7D%7B3%7Da%5CRightarrow%20a%3D-%5Cfrac%7B2%7D%7B-%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Cfrac%7B3%5Ccdot2%7D%7B2%7D%3D%5Cfrac%7B6%7D%7B2%7D%3D3%20%5C%5C%20a%3D3%20%5Cend%7Bgathered%7D)
therefore, a=3
Note: you can also find a if you use the slope formula.
The inverse function of cos is arccos (cos^-1(x)). So, the only one that has arccos(x/6) is option c. That's your answer!