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2 years ago

7

Consider the points below. P(â1, 4, 1), Q(0, 6, 2), R(4, 3, â1)

1 answer:

user100 [1]2 years ago

4 0

Answer:

B. Find the area of the triangle PQR.

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Solve the system of equations 5x-2y=88 3x+4y=58 show all work

diamong [38]

The given equations are:

5x - 2y = 88
3x + 4y = 58

Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
3x + 4y = 58

Adding the two equations, we get:

10x - 4y + 3x + 4y = 176 + 58
13x =234
x = 18

Using the value of x in 1st equation, we get:

5(18) - 2y = 88
- 2y = 88 -5(18)
-2y = -2
y = 1

So, the solution of the equation is (18, 1)

6 0

3 years ago

Read 2 more answers

If p varies directly with T and p =105 when T=400.Find p when T =500

kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3> $k = \frac{21}{80}$ </h3>

So the formula for the variation is

<h2> $p = \frac{21}{80} T$ </h2>

when

T = 500

Substitute it into the above formula

That's

$p = \frac{21}{80} \times 500$

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

7 0

3 years ago

Please help im so confused??

Ann [662]

V = PI x r^2 x h/3

3.14 x 7^2 x 24/3

49 x 8 = 392

answer is 392PI units^3

answer is B

5 0

3 years ago

At Walmart, apples cost $0.50 each, and grapefruits cost $2 each. You want to spend exactly $15.

Papessa [141]

Define the variables: a is the number of apples I can buy g is the number of grapefruits I can buy.

Write the equation: 15 = 0.50a + 2g

6 0

2 years ago

Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo

ehidna [41]

$a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3$

$b=11011000 = 11011_2 \times 2^{000_2} = -(0100_2 + 1) =-(4+1)=-5$

$a+b=-2 = -1 \times 2^{001} = -2 \times 2^{0} = -4 \times 2^{-1}$ etc.

$a+b=-2 = 11111001 = 11110000 = 11100111 = ...$

Hard to select the correct answers without seeing the choices. Let's check a couple,

$11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark$

$11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark$

$11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark$

4 0

3 years ago