Ten students enter a math contest. In how many ways can 1st, 2nd, and 3rd place trophies be awarded?

1 answer:

4 0

After one of them is chosen for 1st, there are only 9 choices for 2nd, and then there are only 8 choices for 3rd... and so on. There are 720 different ways to pick 1st, 2nd, and 3rd place from among 10 original students

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Learning goal: to understand the rules for computing dot products. let vectors a=(2,1,−4), b=(−3,0,1), and c=(−1,−1,2). part a -

miv72 [106K]

For this case we have the following vectors:
$a = (2,1, -4)

b = (- 3,0,1)

c = (- 1, -1,2)$
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
$a.b = (2,1, -4). (- 3,0,1)

a.b = (2) (- 3) + (1) (0) + (-4) (1)

a.b = - 6 + 0 - 4

a.b = - 10$
Answer:
The product point of the vectors a and b is:
$a.b = - 10$

3 0

3 years ago

Ana vende productos de limpieza .Por cada $100 que venda le dan de comisión $30 .¿Cuánto ganará si vende $600?

Ulleksa [173]

Answer:

$180

Step-by-step explanation:

$600/$100 = 6

$600 es 6 veces $100.

Por vender $600 gana 6 veces mas que por vender $100.

6 * $30 = $180

Respuesta: $180

8 0

2 years ago

Please help with the working out

nadya68 [22]

I hope this helps you

m=5

(5^2-5.5+9)^2

(25-25+9)^2

9^2

81

5 0

3 years ago

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Please help quickly, if someone answers quickly I'll give them Brainly.

denis-greek [22]

1. A

I hope this helped! This is because the division of numbers and factors are equal to this.

6 0

2 years ago

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Which of the following expression expressions is equivalent to cos3x/sinxcosx?

77julia77 [94]

Correct Option:
Option B

Solution:
The given expression is:

$\frac{cos(3x)}{sin(x)cos(x)}$

cos(3x) can be written as cos(2x +x). Expanding it, we get:

$cos(3x) = cos(2x+x) \\ \\ 
cos(3x) =cos(2x)sin(x)-sin(2x)cos(x)$

Using this value of cos(3x) in given equation, we get:

$\frac{cos(3x)}{sin(x)cos(x)} \\ \\ 
= \frac{cos(2x)sin(x)-sin(2x)cos(x)}{sin(x)cos(x)} \\ \\ 
= \frac{cos(2x)sin(x)}{sin(x)cos(x)}- \frac{sin(2x)cos(x)}{sin(x)cos(x)} \\ \\ 
= \frac{cos(2x)}{cos(x)} - \frac{sin(2x)}{sin(x)} \\ \\ 
=sec(x)cos(2x)-csc(x)sin(2x)$

8 0

3 years ago

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