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nekit [7.7K]
3 years ago
11

A person's heartbeat is 88 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th

e person live? Disregard leap years.
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0
We can solve this problem by the rule of three.

88 beats-------------------1 minute
3.1*10⁹ beats------------    x

x=(3.1*10⁹ beats * 1 minute) / 88 beats=35227272.73 minutes.

Now, we express this amount of time in years.

1 year=365 days
365 days=365 day*(24 hour/1day)*(24 hour /1day)*(60 minutes /1hour)=
=525600 minutes.

525600 minutes----------------------1year
35227272.73 minutes----------------x
 
x=(35227272.73 minutes * 1year) / 525600 minutes=67.0229 years
≈ 67 years.

Answer:this person can live 67 years.

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Maslowich
How many hours does he rent it?

Either way, the equation would be 30 + 10x

x is the number of hours he rents the digger.

So for example, if he rented it for say 8 hours

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7 0
3 years ago
Betty stopped running half of the way through the run.
Serhud [2]
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6 0
3 years ago
2 1/2r + 1 + 2r = 9 1/10
GalinKa [24]

This should help you here are the steps of your problem :)


2*(1/2)*r+2*r+1 = 9*(1/10) // - 9*(1/10)


2*(1/2)*r+2*r-(9*(1/10))+1 = 0


2*(1/2)*r+2*r-9/10+1 = 0


3*r+1/10 = 0 // - 1/10


3*r = -1/10 // : 3


r = -1/10/3


r = -1/30


r = -1/30


So your answer would be 1/30

4 0
3 years ago
Work out the volume of a cube of edge 5cm?
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L x w x h = volume
volume = 5 x 5 x 5 = 125 cm ^ 3
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%20%28%5Cfrac%7Bx%28x-2%29%7D%7B2-2e%5E2x%7D%20%29" id="TexFormula1" ti
krek1111 [17]

Answer: 0

Step-by-step explanation:

Substituting in x=0, we get

\frac{0(0-2)}{2-2e^{2}(0)}=0

7 0
2 years ago
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