The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.
<h3>What is the distance in kilometres covered by the satellite after 8 revolutions?</h3>
Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;
D = 6371 + (343)×2
Hence, we have; diameter, D = 7057 km.
Hence, the distance travelled after 8 revolutions is;
C = 8 × πd
C = 8 × 3.14 × 7057
C = 177,271.8 km.
Read more on circumference of a circle;
brainly.com/question/20489969
#SPJ1
Answer:
The answer is 57.83
Step-by-step explanation:
find 8% of 45.90 and add 18% of 45.90 and add them together.
8%*45.90=3.67
18%*45.90=8.26
Add, 45.90+8.26+3.67
The final price of your meal is 57.83
Answer:
When a matrix is multiplied by its inverse the result will be the identity matrix. If we multiply two matrix with the same size, the resulting matrix will have the same dimension.
Therefore, if we multiply the matrices X and Y we will get a 2x2 identity matrix, as follows:
![\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
True
Step-by-step explanation:
15/7 is about 2.14 which is less than 3
Answer:
1, 3, 9, 27
Step-by-step explanation:
You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.
n = 1
n = 2
n = 3
n = 4
