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quester [9]
3 years ago
5

How many sigma and pi bonds are in the molecule ch3chch2? 1. 6 sigma and 2 pi 2. 2 sigma and 1 pi 3. 9 sigma and 0 pi 4. 8 sigma

and 1 pi 5. 7 sigma and 2 pi 6. 7 sigma and 1 pi?
Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0
The molecule is as follows;
H₃C---C==CH₂
           |
         H
--- represents single bonds whilst == represents double bonds
Single bonds are formed by sigma orbital head on overlap between sigma orbitals of C and H in the case of C-H bonds and between C sigma orbitals in the case of C-C bonds 
the number of sigma bonds are therefore the number of single bonds which are:
6 C-H bonds
2 C-C bonds
altogether 8 sigma bonds 
p orbitals side- on overlap forms a pi bond. In double bonds, there's one sigma bond and one pi bond.
number of double bonds - 1 C=C therefore one pi bond 
Answer is <span>4) 8 sigma and 1 pi</span>
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Logarithms:
WITCHER [35]

Answer:

  • A) k = 18.75
  • B) R(0.8) = 161419
  • C) R(0.3) = 275

Step-by-step explanation:

<u>Given expression</u>

  • R(x) = 6*e^(kx)

A) <u>Given</u>

  • x = 0.04
  • R = 10

<u>Solving for k</u>

  • 10 = 6*e^(0.04k)
  • e^(0.04k) = 10/6
  • ln (e^0.04k) = ln (1.6666)
  • 0.04k = 0.51
  • k = 0.51/0.04
  • k = 12.75

B) <u>Given</u>

  • x = 0.8
  • R= ?

<u>The value of R(0.8) is:</u>

  • R(0.8) =
  • 6*e^(0.8*12.75) =
  • 6*e^(10.2) =
  • 161419  rounded

C) <u>Given</u>

  • x = 0.3
  • R = ?

<u>The value of R(0.3) is:</u>

  • R(0.3) =
  • 6*e^(0.3*12.75) =
  • 6*e^(3.825) =
  • 275 rounded
4 0
3 years ago
Roberto invested money into two mutual funds. During the first year, Fund
Alexandra [31]
(a*.04)+(b*-.07)=total
3 0
3 years ago
Someone help me on this please
irina [24]

Answer:

C. The triangles are not similar.

Step-by-step explanation:

Divide the short sides and long sides to see if they are similar:

24/16 = 1.5

36/28 = 1.29

The triangles are not similar.

4 0
3 years ago
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Jlenok [28]

Answer:

less than

Step-by-step explanation:

6 0
2 years ago
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Please help! I need this to pass. If you are trying to get points please just chose a different question and don't mess with min
Hunter-Best [27]

Given:

Radius of the cylinder = 2 cm

Height of the cylinder = 3 cm

To find:

The surface area of the cylinder.

Solution:

The surface area of a cylinder is:

A=2\pi rh+2\pi r^2

Where, r is the radius and h is the height of the cylinder.

Putting r=2,h=3,\pi = 3.14, we get

A=2(3.14)(2)(3)+2(3.14)(2)^2

A=37.68+25.12

A=62.8

Therefore, the surface area of the cylinder is 62.8 square cm.

3 0
3 years ago
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