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quester [9]
3 years ago
5

How many sigma and pi bonds are in the molecule ch3chch2? 1. 6 sigma and 2 pi 2. 2 sigma and 1 pi 3. 9 sigma and 0 pi 4. 8 sigma

and 1 pi 5. 7 sigma and 2 pi 6. 7 sigma and 1 pi?
Mathematics
1 answer:
allochka39001 [22]3 years ago
8 0
The molecule is as follows;
H₃C---C==CH₂
           |
         H
--- represents single bonds whilst == represents double bonds
Single bonds are formed by sigma orbital head on overlap between sigma orbitals of C and H in the case of C-H bonds and between C sigma orbitals in the case of C-C bonds 
the number of sigma bonds are therefore the number of single bonds which are:
6 C-H bonds
2 C-C bonds
altogether 8 sigma bonds 
p orbitals side- on overlap forms a pi bond. In double bonds, there's one sigma bond and one pi bond.
number of double bonds - 1 C=C therefore one pi bond 
Answer is <span>4) 8 sigma and 1 pi</span>
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Step-by-step explanation:

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(hit like pls)

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4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=8%20-%203w%20%3D%20%20-%202w" id="TexFormula1" title="8 - 3w = - 2w" alt="8 - 3w = - 2w" ali
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Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

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where,

m(t) =  amount of sample after time 't' = 356 g

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t = time period = 7 days

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Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
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