First differences are 2, 4, 8, 16, which is a geometric sequence. The parent function is not linear (constant first difference) or quadratic (first difference increases by the same amount from one to the next). When the first differences are a geometric sequence, the underlying sequence is a geometric (exponential) sequence.
1st blank: exponential
Translation up adds a constant to each of the f(x) values.
2nd blank: f(x)
3rd blank: increased by 5<span>
For the last blank, you're looking for an (x, f(x)) pair that is translated to (x, f(x)+5).
4th blank: </span><span>(2, 16)</span>
Answer:
I believe it is D
Step-by-step explanation:
If I am correct please mark Brainlyiest
In a trapazoid the diagonals are the same so therefore the two equations equal echother
3x+7=5x-11 solve for x by combining like terms
18=2x then divide to unto multiplication
9=x
9 is the value of x
I hope I've helped!
Let the token profit be X.
For a win, the profit is 2 tokens.
For a loss, the profit is -3 tokens.
The probability of a win is
<span><span>212</span>+<span>212</span>+<span>212</span>=<span>612</span>=<span>12</span></span>
the probability of a loss is
<span><span>612</span>=<span>12</span></span>
Setting up a probability distribution variable gives:
<span>E(X)=(−3×<span>12</span>)+(2×<span>12</span>)=−1<span>12</span>+1=−<span>12</span> token</span><span>
Therefore, on average, the player would expect to lose a half a token per game.</span>
Answer:
Step-by-step explanation:
(x-6)² + y²-8y = 0
Put the equation into center-radius form.
complete the square
coefficient of the y term: -8
divide it in half: -4
square it: (-4)² = 4²
add 4² to both sides to complete the square and keep the equation balanced:
(x-6)² + (y²-8y+4²) = 4²
(x-6)² + ( y-4)² = 4²
center (6,4)
radius 4
