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MaRussiya [10]
3 years ago
5

Add. Reduce to lowest terms. 6 4/5 + 3 7/10 =

Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0

Answer:

10 1/2

Step-by-step explanation:

Converting both mixed numbers to improper fractions, we get 34/5+37/10. Now we can convert them both to have a denominator of 10 and we get 68/10+37/10. Combining, we get 105/10 or 10 1/2.

Len [333]3 years ago
3 0

Answer:

10  1/2

Step-by-step explanation:

The LCD here is 10.

Thus, our  6 4/5 + 3 7/10  becomes 6  8/10 + 3  7/10.

Adding the whole numbers, we get 9; adding the fractions, we get 15/10, or 1 1/2.  Combine this 9 and this 1  1/2:

Thus, our  6 4/5 + 3 7/10 becomes 10  1/2.

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3 beause when you dividend it -5.6+4(3) .

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3 years ago
If Audrey wanted to solve this equation using the square root method, which answer shows the correct sequence of steps?
Fiesta28 [93]

Answer:

C

Step-by-step explanation:

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6 0
3 years ago
In the figure shown, suppose m angle ABC=n and m angle ABD=2(m angle DBC). The angle bisector of angle DBC is BE. What is m angl
Yanka [14]

Answer:

n/6

Step-by-step explanation:

If angle bisector of angle DBC is BE. What is m angle EBC, then <DBE = <EBC

Since <ABC = <ABD+<DBC

n = 2<DBC+<DBC

n = 3<DBC

<DBC = n/3

Since <DBC = 2EBC

n/3 = 2<EBC

n/6 = <EBC

Hence <EBC = n/6

4 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
2+10-4-8+1=<br><br><br> This is for Mark
Lelu [443]

Answer:

1

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Step-by-step explanation:

6 0
3 years ago
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