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iogann1982 [59]
3 years ago
14

What is the point slope form of the line with slope −1/4 that passes through the point (−2, 9) ?

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0

Answer:

Step-by-step explanation:

Point slope form of the equation with point (a,b) and slope m is given by this equation

y-b=m(x-a)

Here we are given that the slope is -1/4 so m= -1/4

and the point is (-2,9) so a =-2 and b =9

Hence plugging the values in the equation we get

y-9 = -1/4 (x-(-2))

y -9 =-1/4 (x+2)

lilavasa [31]3 years ago
5 0
Y - 9 = -1/4 ( x + 2)

answer
<span>y−9=−14(x+2) 
last one</span>
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3.8*10 to the 9th power divided by 4*10 to the 2nd power
user100 [1]

Answer:

9.5\times 10^{6}

Step-by-step explanation:

1. Divide the coefficients and the exponentials separately

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = \dfrac{3.8}{4} \times \dfrac{10^{9}}{10^{2}}

2. Divide the coefficients

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3. Divide the exponentials

Subtract the exponent in the denominator from the exponent in the numerator.

\dfrac{10^{9}}{10^{2}} = 10^{(9 - 2)} = 10 ^{7}

4. Re-join the new coefficient and the new exponential

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = 0.95 \times 10^{7}

5. Put the new number into standard form

The number before the power of 10 must be greater than or equal to one and less than 10.

Multiply the answer by 10/10.

(0.95 \times 10^{7}) \times \dfrac{10}{10} = (0.95\times10) \times \dfrac{10^{7}}{10} = \mathbf{9.5\times 10^{6}}

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3 years ago
What is the area of a hexagonal prism with a side length of 11, a height of 20, and apothem of 9.5? Note: Answer must not be fra
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I assume the solid is a "regular hexagonal prism", by which it means that the cross section is a regular hexagon with all sides and angles equal.
Also, the exact apothem is 9.5262... but we will adopt the given value of 9.5.

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Total area=1320+627=1947 units
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