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Katyanochek1 [597]
3 years ago
9

Plz work out DUE TOMORROW

Mathematics
2 answers:
stira [4]3 years ago
7 0
6/3 = 2/1

2/1 is literally 2

hope this helps

your answer is 2

natulia [17]3 years ago
6 0
6/3 simplified is 2/1

Also known as just 2.
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For each function, what is the output of the given input?
ki77a [65]

Answer:

1.  d. 10.

2. d. 35t + 2.75; $142.75.

Step-by-step explanation:

1.   f(-2) = -2*-2 + 6

    = 4 + 6

    = 10.

2.  The answer is 35t + 2.75

     and the cost of 4 tickets = 35*4 + 2.75 =  $142.75.

4 0
3 years ago
How to find the area of a segment of a circle if r=8 and central angle =120 degrees. Please explain clearly and thoroughly. Will
bekas [8.4K]
First you need to find the area of the circle, which is πr^2
With a radius of 8 inches, the area of the circle will be π*8^2 or 64π.
Next you want to find the area of the 120 degree section of that circle.
120 degrees is 1/3 of a circle, so all you have to do next is multiply the are of the circle by 1/3 (because 360/120= 1/3).
(1/3)(64π) --> All you really have to do here is multiply 64 by 1/3 or divide it by 3 (because to divide by a number is the same a multiplying by it's reciprocal) so you get (64/3)(π).
64/3 is 21 and 1/3 or 21.333..., so however you choose to write it, I will leave the answer as (64/3)π squared inches.
5 0
3 years ago
FAST YOU ANSWER FIRST YOU GET FREE BRAINLIEST
11111nata11111 [884]
-10v^9+8v^6+2v^5

10=5*2
8=2^3
2=2

The common factor is 2 and its least exponent is 1
The least exponent for the variable v is 5

Then, the GFC of the polynomial is 2v^5

Factoring:
2v^5 [ -(10v^9)/(2v^5)+(8v^6)/(2v^5)+(2v^5)/(2v^5) ] =
2v^5 (-5v^(9-5)+4v^(6-5)+1) =
2v^5 (-5v^4+4v+1)
8 0
3 years ago
Read 2 more answers
An engineer is standing 250 meters away from a building. She measures the angle of elevation to the top of the building to be 30
RSB [31]

Answer:

144m

Step-by-step explanation:

we would used tan 30 to determine the height of the building

tan 30 = opposite / adjacent

0.5774 x 250 = 144m

3 0
3 years ago
Two sides of a triangle are given as 28 inches and 42 inches. find all possible lengths for the third side of the triangle
timofeeve [1]
The longest side of  a triangle must be less than the sum of the other 2 sides

2 senarios

the 3rd side is the longest
the 3rd side is not the longest



for the 3rd side is the longest

3rdside<28+42
3rdside<70


for 3rd side isn't the longest
42 is longest
42<28+3rdside
14<3rdside

so we've got
3rdside<70 and 14<3rdside

so
14<3rdside<70

the 3rd side can be any number from 14in to 70in except 14in and 70in
6 0
3 years ago
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