Question

Find the 14th term of the following geometric sequence. 4, 8, 16, 32, ...

Answer 1

Answer:

32768

Step-by-step explanation:

$an = (a1)(r^{n-1} )$

where an stands for the number in the series,

a1 is the first number in the series

and n is the number or the order in which the number in the series we are looking at.  r is the ratio.

in this we case we are looking for the 14th number, where n = 14, the first number is 4 and r is the ratio they increase by a factor of 2. so r = 2.

Substituting all of these back into the equations would give us:

$a14 = 4(2^{13} )$

This will give us the answer.

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Answer 2

Answer:

65536

Step-by-step explanation:

multiply each term by 2 until you get to the 14th term. the 14th term is 65536