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olga55 [171]
3 years ago
9

HELP ON THESE 2 QUESTIONSS PLSSSS

Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

1) the third equation  or X/2=2.0

2)  20 bucks

Step-by-step explanation:

for number 1 just plug in the x hi 4 and try to solve it

2) just calculate unit rate by 120/6=20

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The total surface area of a right circular cylinder is 84 pie cm square and the altitude is 11 cm .find the radius of the base​
djyliett [7]

Answer:

use the formula r = square root of (V / (pi x h))

8 0
2 years ago
Read 2 more answers
Find the volume of the composite solid shown below, Round answer to the nearest hundredth.
MrMuchimi
First you’d start off by finding the volume of the rectangular prism on the bottom. The formula for this is lwh or (length*width*height) so you’d plug in the numbers and get 4*4*5 which multiplies out to be 80inches cubed. Next you’d have to find the volume of the pyramid by using the formula lwh/3 or ((length*width*height)/3) so it would be ((4*4*6)/3) and that equals 32inches cubed. Finally, you add the 2 volumes together so 80inches cubed+32inches cubed and get 112inches cubed. Hope this helps
4 0
2 years ago
()+()+()+()+()=30
Iteru [2.4K]
<span>There are 5 boxes, where we have to put given numbers. Addition of 5 odd numbers always gives an odd number result. 30 is an even number. So there is no combination of given numbers which can give you 30 as a result. 
</span>
3 0
3 years ago
What is the quotient 931/4?
lianna [129]

Answer:

here's a photo of the calculator to that question

3 0
2 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
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