Hello there!
Knowing that the vertex form of the quadratic equation is
y=a(x-h)^2+k where (h,k) represents the vertex, and the a value represents the leading coefficient of the quadratic equation in standard form, first plug in your known values (your given coordinate point can be plugged into the x and y values, and your given vertex can be plugged into h and k):
-4=a(0-10)^2-9
Because your a value is still unknown, you can use your given values in the equation to solve for a:
-4=a(-10)^2-9
-4=100a-9
100a=5
a=1/20
Now that you have your a value, you can plug it into your vertex form as well as your vertex values to get that your equation in vertex form is:
y=1/20(x-10)^2-9
Answer:
2.8888888888889
Step-by-step explanation:
I hope this helps
<span>1. (f+g)(x) = f(x) +g(x)
.. = (</span>x^2-36) +(<span>x^3+2x^2-10)
.. = x^3 +3x^2 -46
2. </span>(f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81
<span>3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10</span>
Answer:
tolong tandai saya cerdas
Step-by-step explanation:
tentu aku akan senang berteman denganmu
Step-by-step explanation:
Solution:
(6xy) × (-3x²y³)
= {6 × (-3)} × {xy × x²y³}
= -18x1+2 y1+3
= -18x³y⁴.
