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3 years ago

What is x -3 =10 pls show work

Mathematics

2 answers:

VashaNatasha [74]3 years ago

7 0

You add three to both sides.

x − 3 + 3 = 10 + 3

x = 13

Therefore, your answer is x = 13.

LiRa [457]3 years ago

7 0

Answer:

x= 13

Step-by-step explanation:

x-3 =10

x= 10+3

x= 13

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Please help me answer this question

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The value of dy/dx for the functions are

(i) $\frac{dy}{dx} = 4x^{2}sin2x.cos2x+ 2x. sin^{2}2x$

(ii) $\frac{dy}{dx} =\frac{- y(1+3x^{2})}{2x(1+x^{2}) }$

<h3>Differentiation</h3>

From the question, we are to determine dy/dx for the given functions

(i) $x^{2} sin^{2}2x$

Let $u = x^{2}$

and

$v = sin^{2} 2x$

Also,

Let $w= sin2x$

∴ $v = w^{2}$

First, we will determine $\frac{dv}{dx}$

Using the Chain rule
$\frac{dv}{dx} = \frac{dv}{dw}.\frac{dw}{dx}$

$v = w^{2}$

∴ $\frac{dv}{dw} =2w$

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$\frac{dv}{dx} = 2w \times 2cos2x$

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Now, using the product rule

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From above

$u = x^{2}$

∴ $\frac{du}{dx}=2x$

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(ii) $xy^{2}+y^{2}x^{3} +2=0$

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$2xy\frac{dy}{dx}+2x^{3}y\frac{dy}{dx} =- y^{2}-3x^{2}y^{2}$

$\frac{dy}{dx} (2xy+2x^{3}y)=- y^{2}(1+3x^{2})$

$\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy+2x^{3}y}$

$\frac{dy}{dx} =\frac{- y^{2}(1+3x^{2})}{2xy(1+x^{2}) }$

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Learn more on Differentiation here: brainly.com/question/24024883

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What is x -3 =10 pls show work​

What is x -3 =10 pls show work