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MariettaO [177]
3 years ago
12

Which of the following statements about anabolic pathways is true?

Chemistry
2 answers:
nadezda [96]3 years ago
8 0

Answer:

They consume energy to build up polymers from monomers.

Explanation:

Anabolic reactions are the metabolic reactions performed in the body which synthesizes the large molecules from the small molecules or synthesizes polymers from the monomers.

The synthesis of polymers requires energy which is provided during the reaction by ATP, NADH or NADPH molecules.

The examples of anabolism include the synthesis of biomolecules like the nucleic acid from the nucleotides, the synthesis of proteins from the amino acids, the synthesis of sugars from the carbon dioxide and water and many others.

Thus, the selected option is the correct answer.

Sedbober [7]3 years ago
6 0

Answer:

They consume energy to build up polymers from monomers.

Explanation:

Metabolism may be defined as all the biochemical reactions that are present in the living organisms. These reactions are important for the sustenance of the life.

Two main type of metabolic reactions are catabolic reaction and anabolic reactions. The anabolic reactions includes the formation of the large product from the small molecules. The large compounds are synthesized in the cells in the anabolic reactions.

Thus, the correct answer is option (2).

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A compound with the molecular formula C10H10O4 produces a 1H NMR spectrum that exhibits only two signals, both singlets. One sig
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Answer:

The attached figure shows the structure of dimethyl terephthalate.

Explanation:

Dimethyl terephthalate is a compound whose formula is C6H4 (COOCH3) 2. It is a diester produced from terephthalic acid and methanol. It is characterized by being a white solid. Another method for the preparation is from p-xylene and methanol, which is characterized by having an oxidation and an esterification.

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3 years ago
Tin hydrogenooxolate formula
vladimir2022 [97]

Answer:

Tin(IV) Hydrogen Oxalate. Alias: Stannic Hydrogen Oxalate. Formula: Sn(HC2O4)4. Molar Mass: 474.8178. :: Chemistry Applications:: Chemical Elements, Periodic Table.

Explanation:

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3 years ago
Read 2 more answers
Simplify - Factor a
Dmitriy789 [7]

Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

7 0
2 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

7 0
3 years ago
The molecular formula for butane is C4H10. Determine the percent composition for
masya89 [10]

%Mass

Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

\tt C=\dfrac{4.12}{58}\times 100\%=82.8\%\\\\H=100\%-82.8\%=17.2\%

or

\tt H=\dfrac{10.1}{58}\times 100\%= 17.2\%

4 0
2 years ago
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