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Len [333]
3 years ago
14

For this reaction S2O82-(aq) 3I-(aq)----2SO42-(aq) I3-(aq), we can use spectrophotometer to decide the concentration due to___is

colored
Chemistry
1 answer:
Alika [10]3 years ago
8 0

Answer:

I3-(aq)

Explanation:

To measure the rate of this reaction we must measure the rate of concentration change of one of the reactants or products. This reaction may also be referred to as the iodine clock reaction. It yields the triodide ion which forms a blue complex with starch which enhances the determination of iodine even though iodine is coloured also.

Since the reaction is monitored by spectrophotometry, the concentration of the triodide ion can be monitored by spectrohotometric detection of the concentration of triodide ion present in the system. Hence we can use the determination of the amount of triodide ion by spectrophotometry to understudy this reaction.

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One of the products of photosynthesis is<br> carbon dioxide.<br> fire.<br> oxygen gas.<br> mass.
kondor19780726 [428]
One of the products of photosynthesis is carbon dioxide
5 0
3 years ago
Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
Fish need about 5 ppm oxygen dissolved in water to survive. Will water with 5 mg oxygen per
Lelechka [254]

5mg in liter is 5 ppm

Explanation: 1 ppm is one part per million.

1 ppm is 1 mg is one part of million from 1 kg = 1000 000 mg

1 litre water is 1. Kg.

3 0
3 years ago
PLZ HELP OR WILL FAIL!!
lianna [129]
Hey there!

Label A: Sublimation
Label B: Condensation
Label C: Melting

Remember sublimation is the transition of a substance directly from the solid to the gas state, without passing through the liquid state. Condensation is the conversion of a vapor or gas to a liquid. Melting is becoming liquefied by heat.

Hope this helps!
5 0
3 years ago
14.A sample of fluorine gas has a density of _____
yarga [219]

Answer:

d = 0.793 g/L

Explanation:

Given data:

Density of fluorine gas = ?

Pressure of gas = 0.554 atm

Temperature of gas = 50 °C (50+273.15K = 323.15 K)

Solution:

Formula:

PM = dRT

M = molar mass of gas

P = pressure

R = general gas constant

T = temperature

d = PM/RT

d = 0.554 atm × 37.99 g/mol / 0.0821 atm.L /mol.K × 323.15 K

d = 21.05 atm.g/mol/26.53 atm.L /mol

d = 0.793 g/L

8 0
3 years ago
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