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Oxana [17]
3 years ago
13

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upp

er H superscript minus right arrow upper H subscript 2 upper O. Upper H upper N upper O subscript 3 plus upper N a upper O upper H right arrow upper N a upper N upper O subscript 3 plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus plus upper N a superscript plus, plus upper O upper H superscript minus right arrow upper N a superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper O upper H superscript minus right arrow upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O.
Chemistry
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Explanation:

Chemical equation:

HNO₃ + NaOH →  NaNO₃ + H₂O

Balanced chemical equation:

HNO₃(aq) + NaOH(aq) →  NaNO₃(aq) + H₂O(l)

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The NO₃⁻ (aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation

Nonamiya [84]3 years ago
3 0

Answer:

Its C on edge2020

Explanation:

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In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
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Answer: 1.14

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HCl+NaOH\rightarrow NaCl+H_2O

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n_1M_1V_1=n_2M_2V_2

where,

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are the n-factor, molarity and volume of base which is NaOH.

We are given:

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3 years ago
Four acids are analyzed and there KA values are determined which of the following values represents the strongest acid
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x= the coefficients in front of the substance in the balanced chemical equation  

[H+]= the concentration of hydrogen ions  

[A-]= the concentration of the other ion that broke off from the H+  

[HA]= the un-disassociated acid concentration  

The higher the Ka value, the greater amount of disassociation of the reactants into products. As for acids, they will break down to form H+ ions. The more the H+ ions, the stronger acidity of the solution. Thus since A has the highest Ka value, that represents the strongest acid.  

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Hope this helped a little, its obviously not my best work

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