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Oxana [17]
3 years ago
13

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upp

er H superscript minus right arrow upper H subscript 2 upper O. Upper H upper N upper O subscript 3 plus upper N a upper O upper H right arrow upper N a upper N upper O subscript 3 plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus plus upper N a superscript plus, plus upper O upper H superscript minus right arrow upper N a superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O. Upper H superscript plus, plus upper N upper O subscript 3 superscript minus, plus upper O upper H superscript minus right arrow upper N upper O subscript 3 superscript minus, plus upper H subscript 2 upper O.
Chemistry
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Explanation:

Chemical equation:

HNO₃ + NaOH →  NaNO₃ + H₂O

Balanced chemical equation:

HNO₃(aq) + NaOH(aq) →  NaNO₃(aq) + H₂O(l)

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The NO₃⁻ (aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation

Nonamiya [84]3 years ago
3 0

Answer:

Its C on edge2020

Explanation:

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42.6 g Cu are combined with 84.0 g HNO3 according to reaction:
bekas [8.4K]

Answer:

Mass of Cu(NO₃)₂ produced = 125.67 g

limiting reactant = Cu

Explanation:

Given data:

Mass of Cu = 42.6 g

Mass of HNO₃ = 84.0 g

What is limiting reactant = ?

Mass of Cu(NO₃)₂ produced = ?

Solution:

Chemical equation:

3Cu + 8HNO₃    →     3Cu(NO₃)₂ + 4H₂O + 2NO

Number of moles of Cu:

Number of moles = mass/ molar mass

Number of moles = 42.6 g/63.546 g/mol

Number of moles = 0.67 mol

Number of moles of HNO₃:

Number of moles = mass/ molar mass

Number of moles = 84 g/63.01 g/mol

Number of moles = 1.3 mol

Now we will compare the moles of Cu(NO₃)₂ with HNO₃ and Cu from balance chemical equation.

                    HNO₃         :        Cu(NO₃)₂

                       8              :         3

                      1.3             :       3/8×1.3 = 6

                    Cu              :           Cu(NO₃)₂

                      3               :              3

                      0.67          :           0.67

Number of moles of Cu(NO₃)₂ produced by Cu are less so Cu will limiting reactant.

Mass of Cu(NO₃)₂:

Mass = number of moles × molar mass

Mass = 0.67 mol × 187.56 g/mol

Mass = 125.67 g

7 0
3 years ago
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