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boyakko [2]
3 years ago
15

1. IQ scores of statistics students have a standard deviation less than 15. A. H0:σ≤15, H1:σ>15 B. H0:σ≥15, H1:σ<15 C. H0:

µ<15, H1:µ≥15 D. H0:µ≤15, H1:µ>15 2. The mean salary of statistics professors is at most 70,000 dollars. A. H0:µ<70,000, H1:µ≥70,000 B. H0:µ>70,000, H1:µ≤70,000 C. H0:µ≥70,000, H1:µ<70,000 D. H0:µ≤70,000, H1:µ>70,000 3. More than one-half of all Internet users make on-line purchases. A. H0:µ≥0.5, H1:µ<0.5 B. H0:µ≤0.5, H1:µ>0.5 C. H0:p≥0.5, H1:p<0.5 D. H0:p≤0.5, H1:p>0.5
Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

Answer:

1) For this case we want to check if the population deviation is less than 15( alternative hypothesis) and the system of hypothesis are:

H0: \sigma \geq 15

H1: \sigma

B. H0:σ≥15, H1:σ<15

2) For this case we want to check if the population mean \mu is at most 70000 (alternative hypothesis) and the system of hypothesis are:

H0: \mu \geq 70000

H1: \mu

C. H0:µ≥70,000, H1:µ<70,000

3) For this case we want to check if the population proportion p of all internet users that make online purchases is higher than 0.5 (alternative hypothesis) and the system of hypothesis are:

H0: p \leq 0.5

H1: p >0.5

D. H0:p≤0.5, H1:p>0.5

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Solution to the problem

1) For this case we want to check if the population deviation is less than 15( alternative hypothesis) and the system of hypothesis are:

H0: \sigma \geq 15

H1: \sigma

B. H0:σ≥15, H1:σ<15

2) For this case we want to check if the population mean \mu is at most 70000 (alternative hypothesis) and the system of hypothesis are:

H0: \mu \geq 70000

H1: \mu

C. H0:µ≥70,000, H1:µ<70,000

3) For this case we want to check if the population proportion p of all internet users that make online purchases is higher than 0.5 (alternative hypothesis) and the system of hypothesis are:

H0: p \leq 0.5

H1: p >0.5

D. H0:p≤0.5, H1:p>0.5

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Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A,              3·p²

0,               0

1,                1

2,               12

3,               27

4,               48

5,               75

6,               108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

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