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Stolb23 [73]
3 years ago
9

1. What is the fourth term in the expansion of (x + 4y)^6?

Mathematics
1 answer:
aev [14]3 years ago
7 0
For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3
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given which of the following describes the boundary line and shading for the second inequality in the system
11Alexandr11 [23.1K]

Answer:

Solid Line, Shade Above

Explanation:

Given:

\left\{\begin{array}{l}
y

The second inequality in the system is:

y\geq x-4

The intercepts of the boundary line (y=x-4) are (0, -4) and (4,0).

Since the inequality has an equal to sign attached, we use a solid line.

At (0,0)

\begin{gathered} y\geq x-4 \\ 0\geq-4 \end{gathered}

Since the inequality 0≥-4 is true, shade the side that contains (0, 0) as shown in the graph below:

So, we use a solid line and shade above the boundary line.

8 0
1 year ago
Twice a number increased by 8 is less than -4
stepladder [879]

Answer:

Twice a number : 2x

increased by : +

8  :  8

is equal to : =

the number : x

increased by :  -

-4  :  -4

The answer is 2x+8 < -4


5 0
3 years ago
Is this a function pls help ASAP
bazaltina [42]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
Let $f(x) = x^2 + 4x - 31$. for what value of $a$ is there exactly one real value of $x$ such that $f(x) = a$?
enot [183]

To solve for this, we need to find for the value of x when the 1st derivative of the equation is equal to zero (or at the extrema point).

So what we have to do first is to derive the given equation:

f (x) = x^2 + 4 x – 31

 

Taking the first derivative f’ (x):

f’ (x) = 2 x + 4

 

Setting f’ (x) = 0 and find for x:

2 x + 4 = 0

x = - 2

 

Therefore the value of a is:

a = f (-2)

a = (-2)^2 + 4 (-2) – 31

a = 4 – 8 – 31

a = - 35

7 0
3 years ago
Write the expanded form of the expression. 6(4x - 8) simplify your answer.
Lynna [10]

Answer:

Step-by-step explanation:

Use distributive property,

a*(b - c) =a*b - a*c

6(4x  - 8) = 6*4x - 8*6

               = 24x - 48

5 0
2 years ago
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