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3 years ago

1. What is the fourth term in the expansion of (x + 4y)^6?

Mathematics

1 answer:

aev [14]3 years ago

7 0

For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3

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2 years ago

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

$7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}$

Therefore this is the simplified radical expression: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

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3 years ago