What is the solution of the equation 16-17+ Vb=1? b = 3 O b = 9 O b = 81 no solution

The diagram shows a hexagon-shaped tile used for flooring. Each hexagon tile has an area of 18/3 in 2 Find x.

mylen [45]

Answer:

x = 12

Step-by-step explanation:

The hexagonal tile given here is made up of 6 triangles with equal bases and heights.

So, area of hexagonal tile will be equal to 6 times the area of one triangle.

Therefore,

$18 \sqrt{3} = 6 \times \frac{1}{2} \times 2 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{x}{6} } \\ \\ 18 \sqrt{3} = 6 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{2x}{12} } \\ \\ \frac{18 \sqrt{3} }{6} = {( \sqrt{3)} }^{ \frac{x}{12} + \frac{2x}{12} } \\ \\ 3 \sqrt{3} = {( \sqrt{3)} }^{ \frac{3x}{12} } \\ \\ 3. {3}^{ \frac{1}{2} } = {3}^{ \frac{3x}{24} } \\ \\ {3}^{1 + \frac{1}{2} } = {3}^{ \frac{x}{8} } \\ \\ {3}^{ \frac{3}{2} } = {3}^{ \frac{x}{8} } \\ (bases \: are \: equal \: so \: exponents \: \\ will \: also \: be \: equal) \\ \implies \frac{3}{2} = \frac{x}{8} \\ \\ x = \frac{3 \times 8}{2} \\ \\ x = 3 \times 4 \\ \\ x = 12$

7 0

3 years ago

Read 2 more answers

Will mark Brainlest!! Help Please! (1). find the domain and range of the following

miss Akunina [59]

Answer:

Step-by-step explanation:

You have the domain. It is given as -1≤x≤1

Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.

Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0

I've included a graph so you can see how this all works.

So the range = 1 ≤ y ≤ 3

5 0

3 years ago

Find the value of f(-1) for the function below

mrs_skeptik [129]

Put the value of x = -1 to the equation of a function f(x):

$f(x)=\dfrac{2}{3}\times3^{3x+12}\\\\f(-1)=\dfrac{2}{3}\times3^{3(-1)+12}=\dfrac{2}{3}\times3^{-3+12}=\dfrac{2}{3}\times3^9=\dfrac{2}{1}\times3^8=13,122\to\boxed{B.}$