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2 years ago

giving brainliestsuppose cos(x)=-1/3, where pi/2=<x=<pi. what is the value of tan(2x)?

Mathematics

1 answer:

qaws [65]2 years ago

4 0

Answer:

4√2/7

Step-by-step explanation:

Suppose cos(x)=-1/3, where pi/2≤x≤ pi

tan(2x) = sin(2x)/cos(2x)

Since sin2x = 2sinx cosx

cos 2x = 2cos²x-1

Substitute

tan(2x) = 2sinx cosx/ 2cos²x-1

Given cosx = -1/3

adjacent = -1

hyp = 3

opp = √3²-(-1)²

opp = √9-1

opp = √8

sinx = opp/hyp

sinx = √8/3

tan(2x) = 2sinx cosx/ 2cos²x-1

tan(2x) = 2(√8/3)(-1/3)/ 2(-1/3)²-1

tan2x= (-2√8/9 )÷ (2/9 - 1)

tan2x = -4√2/9 * 9/-7

tan 2x = 4√2/7

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3 years ago

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3 years ago

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I remember that the square of 12 is 144.
Let's work up from there to the squares that 180 lies between.

Keep in mind that squares are when a number multiplies by itself.

For example;
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Well, we have 169 and 196, which 180 lies between.

Your answers are:

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I hope this helps!

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3 years ago

*giving brainliest*suppose cos(x)=-1/3, where pi/2=<x=<pi. what is the value of tan(2x)?​

giving brainliestsuppose cos(x)=-1/3, where pi/2=<x=<pi. what is the value of tan(2x)?