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Rufina [12.5K]
3 years ago
12

Really quick and ill be out of your hair.....unless your bald LOL

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
Perpendicular lines are lines that intersect, so they are perpendicular.
Vesnalui [34]3 years ago
5 0
Perpendicular lines I think I don't want you to be wrong but i Googled it and it popped up some weir lines hope I helped
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NEED HELP<br><br> evaluate<br> a+b/c <br> if a = -28 b = -35 and c = -3
monitta

Answer:

21

Step-by-step explanation:

(-28-35)/-3

-63/-3

21

7 0
3 years ago
Fill in the blanks with two rational numbers (other than 1 and −1).
MA_775_DIABLO [31]

Answer:

2 and 20

Step-by-step explanation:

First how can we get rid of the fraction?

We can multiply -1/2 by 2 to get -1

Next what number do we multiply to get from -1 to -20?

-1x = -20

divide both sides by -1

x = 20

please give thanks by clicking the heart :)

7 0
2 years ago
What is the square root of -16<br><br> -8i<br> -4i<br> 4i<br> 8i<br><br><br><br> Pls explain tooo
erik [133]
4i,
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
3 0
3 years ago
Help me solve,Brainlist for first to answer
Vanyuwa [196]

Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

                      =  6² + 6²

                      = 36 + 36

                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

the other two sides are 6 and  6\sqrt{2}

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

                       3 d = 4

therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

                                     =\frac{8}{3}

the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

7 0
3 years ago
What is the eqivalent of (x-2)(x+4)?<br>Will get brianly thing!!!!!!!!
Xelga [282]

Answer:

Equivalent is

  • x^2+2x-8
  • 2x^2+4x-16

8 0
2 years ago
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