Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.
Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.
Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:
60x + 80y ≤ 360
For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:
160x + 120y ≤ 680
To calculate how many of each type you need:
60x + 80y ≤ 360
160x + 120y ≤ 680
Isolating x from the first equation:
x = 
Substituing x into the second equation:
160() + 120y = 680
-3200y+1800y = 10200 - 14400
1400y = 4200
y = 3
With y, find x:
x =
x = 
x = 2
To determine the cost:
cost = 42,000x + 51,000y
cost = 42000.2 + 51000.3
cost = 161400
To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400
Answer:
This system has no solutions.
Step-by-step explanation:
If we try to solve:
- 5x + 8 = 5x + 3
- 5x + 8 - 3 = 5x
- 5x + 5 = 5x
- 5x - 5x + 5 = 5x - 5x
- 5 = 0
Since there are no x values left over and the remaining solution is zero, there is no solution for this equation.
Hope this helps!!
Answer: b≥-3
Step-by-step explanation:
at least means that it's great or equal than -3.
b≥-3
Answer:
16
Step-by-step explanation:
(x-8)^2 + (y-4)^2= 16
The amount of money he lose on the last tool set is: $30.60.
<h3>Amount lose</h3>
Using this formula
Amount lose=Original amount paid -Selling price
Where:
Original amount paid=$54.60
Selling price=$24.00
Let plug in the formula
Amount lose=$54.60-$24.00
Amount lose=$30.60
Therefore the amount of money he lose on the last tool set is: $30.60.
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