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3 years ago

9

What is the approximate volume of a cone with a height of 12 in and radius of 9 in ? Use 3 14 to approximate pi, and express you

r final answer to the nearest hundredth Enter your answer in the box

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

1017.36

Step-by-step explanation: The formula for cone volume is 3.14(r^2)(h/3). Plug in all of your values to get the answer.

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F(x) = 3x + 2 and g(x) = x + 5

hjlf

Answer:

G(f(x)) = A. 3x + 7

Step-by-step explanation:

Plug F(x) into the x on G. so (3x+2) +5 = 3x+7

5 0

2 years ago

What is the area of this figure! Pls help!

nydimaria [60]

Answer:

count all the boxes it covers(that is your area)

answer : 27

Step-by-step explanation:

8 0

2 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

2 years ago

Without graphing classify each system as independent dependent or inconsistent -x -y=7<br> 5x-5y=5

jek_recluse [69]

Answer:

Is a consistent independent system

Step-by-step explanation:

we have

$-x-y=7$ -----> isolate the variable y

$y=-x-7$ ----> equation A

$5x-5y=5$ -----> isolate the variable y

$y=x-5$ ---> equation B

Compare equation A and equation B

We can affirm that

The slopes are not equal ( so the lines are not parallel)

The lines are different

The product of their slopes is equal to -1 (the lines are perpendicular)

so

The system of equations has only one solution

therefore

Is a consistent independent system

5 0

2 years ago

Reem earns $16 per hour for the first 8 hours of her shift. For each additional hour she works beyond the first 8 hours, she ear

RideAnS [48]

The single shift worked by Reem is 16 hours long.

Total earned = $320

First 8 hours (earning per hour) = $16

Additional hours = $24 per hour

Let the total number of hours worked = m

The Number of hours after 8 hours = m - 8

Representing the scenario with an equation :

(16 × 8) + (24 × (m - 8)) = 320

128 + 24m - 192 = 320

-64 + 24m = 320

24m = 320 + 64

24m = 384

Divide through by 24

m = 384 / 24

m = 16

Hence, the shift is 16 hours long.

Learn more : brainly.com/question/18109354

8 0

2 years ago