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Elan Coil [88]
3 years ago
15

Find the rule for the sequence First term: 2 3/4 Sixth term: 3 7/12 Rule:_______

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
K, so areitmetic

an=a1+d(n-1)
a1=first term
d=common differnce

we are given
a1=2 and 3/4
6th term is 3 and 7/12

so

a6=3 and 7/12=2 and 3/4+d(6-1)
3 and 7/12=2 and 3/4+d(5)
minus 2 and 3/4 both sides
10/12=5d
divide both sides by 5 or multiply both sides by 1/5
2/12=d
1/6=d


a_n=2 \frac{3}{4}+ \frac{1}{6}(n-1) or
a_n=2 \frac{7}{12}+ \frac{1}{6}n
that is the rule
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The dependent variable for this experiment is the ability of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment which depends on the presence or absence of noise outside the classroom.

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The dependent variable is the one whose value, form or outcome is determined by one or more other variable(s) in the experiment.

This experiment tests the abilities of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment.

This ability was made to depend on whether there was noise or no noise outside their classrooms.

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<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

\sf{\rightarrow{d =  kt}}

\sf\rightarrow{20  = 2k }

\sf\rightarrow{K= \frac{20}{2} }

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<h2><u>Answer</u>:-</h2>
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