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kherson [118]
3 years ago
5

The moon is about 240,000 miles from Earth. What is the distance written as a whole number multiplied by a power of ten?

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

We need to find 240,000 written as a whole number multiplied by a power of ten.

We need to get rid of the four zeros behind 24 in 240,000.

24 would be our whole number.

We would need to multiply 24 by 10,000 to get 240,000.

10,000 is equal to 10^{4} because there are 4 zeros. Ex. when multiplying 200 by 30, we first multiply 2 * 3 then we add 3 zeros to the end of  6. So for 10*10*10*10, we add 4 zeros to the end of 1 which equals 10,000.

So the answer would be 24 × 10^{4}

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The function = 3describes the volume of a cube, , in cubic inches, whose length, width, and height each measure inches. Find the
kolezko [41]

The correct structure of the question is as follows:

The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.

Answer:

Step-by-step explanation:

Given that:

f(x) = x^3

Then;

V = x^3

The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V

dV/dx = 3x^2

Now, at the moment when x = 3;

dV/dx = 3(3)^2

dV/dx = 3(9)

dV/dx = 27 cubic inch per inch

Suppose it is at the moment when x = 9

Then;

dV/dx = 3(9)^2

dV/dx = 3(81)

dV/dx = 243 cubic inch per inch

6 0
3 years ago
If 6^4x = 82, what is the value of x?<br> Round your answer to three places.
neonofarm [45]

Answer:

x=0.61485921

Step-by-step explanation:

The given equation is in exponential form:

6^{4x} =82

To find x we need to write it in logarithmic form:

b^{a} =n ⇒ log_{b} n=a

6^{4x} =82 ⇒ log_{ 6 }  82=4x

           2.45943684 = 4x

              \frac{2.45943684}{4} = x

           0.61485921 =x

To prove this, we can substitute the value into the given equation

             6^{4x} =82

6^{4(0.61485921)} =82

               82=82

Therefore, the answer is x=0.61485921

6 0
3 years ago
Given that f(x)=x2-1 and g(x)=2x+8 find (g-f)(10)
irga5000 [103]

Answer:

<h2>(g-f)(10) = - 71</h2>

Step-by-step explanation:

f(x) = x² - 1

g(x) = 2x + 8

To find (g-f)(10) first find ( g - f)(x)

To find ( g - f)(x) subtract f(x) from g(x)

That's

( g - f)(x) = 2x + 8 - ( x² - 1)

Remove the bracket

( g - f)(x) = 2x + 8 - x² + 1

Simplify

( g - f)(x) = - x² + 2x + 9

To find (g-f)(10) substitute the value in the bracket that's 10 into ( g - f)(x)

That is

(g-f)(10) = -(10)² + 2(10) + 9

= - 100 + 20 + 9

= - 100 + 29

= - 71

Hope this helps you

7 0
3 years ago
In a small town, the use of coal (W in tons/per
zimovet [89]

Answer:

i)W = 2500 / T

ii)  W = 500 Tons

iii) grad W(10°) = - 25î

iv) The formulation is not practical

Step-by-step explanation:

i)  Write an equation describing the use of coal

As use of coal is inversely proportional to the average monthly temperature

if  W is use of coal in tons/per month then

W(t)  =   k / T              where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions

k  =  ??   we know that when   T  =  25°    W = 100 tons  the by subtitution

W = k/T           100  =  k /25       k  =  2500 Tons*degree

Then final equation is:

W = 2500 / T

ii) Find the amount of coal when T = 5 degrees

W = 2500 / 5

W = 500 Tons

iii)

The inverse proportionality implies that W will decrease as T increase.

The vector gradient of W function is:

grad W  = DW(t)/dt î  

grad W  = - 2500/T² î

Wich agrees with the fact that W is decreasing.

And when T = 100°

grad W(10°) =  - 2500/ 100 î      ⇒  grad W(10°) = - 25î

iv) When T =  0  The quantity of coal tends to infinite and the previous formulation is not practical

5 0
3 years ago
7r-5r+8=9r+8-r translate to an equation, then solve
pshichka [43]

Answer:

r=0

Step-by-step explanation:

7r-5r+8=9r+8-r

This is already an equation

Combine like terms

2r+8 = 8r+8

Subtract 2r from each side

2r-2r +8 = 8r-2r +8

8 =6r+8

Subtract 8 from each side

8-8 = 6r+8-8

0 = 6r

Divide by 6

0/6 = 6r/6

0 =r

7 0
3 years ago
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