That is Slope Form. They should give you two coordinates and you substitute them in.
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
(2)/(3) =( 4)/( 3+x)
Cross multiply
2*(3+x)= 4*3
Solve bracket
6+2x=12
Subtract 6 from both sides
2x=6
Divide both sides by 2
x=3
Hope it helps :-)
The question is incorrect. X is not defined UNLESS the hexagon is a regular hexagon, which means that all sides are equal (given) AND all angles are equal (not given).
Error in question aside, and ASSUMING the hexagon is regular, you can apply the principle that
1. the sum of exterior angles of ANY polygon is 360.
2. the sum of exterior angles and interior angles at EACH vertex is 180.
3. Multiply sum from (2) above by the number of vertices and subtract 360 gives the sum of the interior angles.
4. IF the polygon is regular (all angles equal), then each interior angle equals the result from (3) divided by n, the number of vertices.
Example for a regular heptagon (7 sides, 7 verfices).
1. Sum of exterior angles = 360
2. sum of interior and exterior angles at EACH vertex=180
3. multiply 180 by 7, subtract 360
180*7-360=900
4. since heptagon is regular, each interior angle equals 900/7=128.57 deg.