Need help asap or Im going to fail this class
1 answer:
Answer:
The first four.
Step-by-step explanation:
There are 3 main postulates. SSS, SAS, and AAS. This simply refers to how we prove a triangle congruent. With SSS, all 3 sides must be congruent (either proven or given). AAS is when you have 2 angles congruent with a side next to one of the angles. NOT IN BETWEEN (there's an image as to what I'm talking about below). Finally, SAS. This is when you have a set of angles congruent with sides on each side congruent as well (look at the first four as an example of this.
Any more specific questions, feel free to ask!
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Answer:
Null hypothesis:
Alternative hypothesis:
a. Reject the null hypothesis
c. There is enough evidence to support the claim
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
represent the population standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
z would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses to be tested
We need to conduct a hypothesis in order to determine if the smoking age has significantly changed since the invention of ENDS—electronic nicotine delivery systems, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Compute the test statistic
We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:
(1)
z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
We can replace in formula (1) the info given like this:
What do you conclude? Using the p-value approach
Since is a two tailed test the p value would be:
Since the then the correct decision is:
a. Reject the null hypothesis
And the best conclusion is :
c. There is enough evidence to support the claim
Answer:
The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 30 - 1 = 29
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.462
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 375 - 41.13 = 333.87 kWh
The upper end of the interval is the sample mean added to M. So it is 375 + 41.13 = 416.13 kWh
The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).