(See the imagine for reference)
Let’s solve where they have a triangle, so the height is 9 cm, the base is 3 cm:
1/2 • 9 • 3 = 13.5
Since there’s 2 triangles we do:
13.5(2) = 27
Now the rectangle in the middle, where the height is 9cm and the base is 12cm:
12 • 9 = 108
Add up the areas:
108 + 27 = 135
Answer:
y= -3/5x + 2
Step-by-step explanation:
Answer:
23.7m
Step-by-step explanation:
Given parameters:
Time taken = 2.2s
Acceleration due to gravity = 10m/s
Unknown:
Depth of the well = ?
Solution:
To solve this problem, we simply apply one of the motion equations;
S = ut +
gt²
where S = depth of the well
u = initial velocity
t = time taken
g = acceleration due to gravity
Input the parameters and solve for S;
Note initial velocity = 0;
S =
x 9.8 x 2.2²
S = 23.7m
Answer:
d. 16x² + y² = 16
Step-by-step explanation:
Standard form of an ellipse is:
x² / a² + y² / b² = 1
If b > a, the ellipse has a vertical orientation.
We can ignore options b and c, since they have minus signs in them.
Convert the other options to standard form:
a. x² / (1/16) + y² / (1/25) = 1
x² / (1/4)² + y² / (1/5)² = 1
1/4 > 1/5
d. x² + y² / 16 = 1
x² / 1² + y² / 4² = 1
1 < 4
e. x² / 16 + y² = 1
x² / 4² + y² / 1² = 1
4 > 1
Of these three options, only d is a vertical ellipse.
Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:


Z = 1.16
Z = 1.16 has a p-value of 0.877.
0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1