Reflections and glide reflections both give you a transformation where the preimage and image have opposite orientations.
Answer:
Step-by-step explanation:
From the graph, we can conclude the following points:
1. Number of zeros = 4 ( As the graph intersects or touches the x axis at 4 points.)
2. Number of turning points are 6. ( As there are 3 minimums and 3 maximums)
3. Number of zeros with even powers are 3. ( As the graph touches the x axis at 3 points)
Among all the four options, only the first option fulfills all the above points.
The above function has 4 zeros at 
The above function has 3 even zeros 
Now, number of turning points for the above function is given as:
Turning points = Number zeros + Number of even zeros - 1 = 4 + 3 - 1 = 6
Therefore, the correct option is option 1.
Answer:
MN
Step-by-step explanation:
A cord is a line that has two points on the outer-rim of the circle, but does NOT go through the center
If it’s parallel the slope will always be 0
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
