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marusya05 [52]
3 years ago
7

Which compound inequality is represented by the graph​

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

-2 < x < = 4

Step-by-step explanation:

Cause the dot at -2 isn't full, means that it's not equal to it.

The opposite thing happens at 4

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I needd help is due today at 3pm qnq!!
masha68 [24]
The answer is c, since they both add up to 90°
3 0
3 years ago
I need help solving this problem
guapka [62]

Answer:

- 5/13

Step-by-step explanation:

tans = 5/12 = height/base

Using Pythagoras, hypotenuse = √12² + 5² = 13

Therefore coss had to be 12/13

But since cos s < 0, cos s = - 12/13

Thus,

tanA = sinA/cosA

tanA cosA = sinA

(5/12)(- 12/13) = sinA

- 5/13 = sinA

8 0
3 years ago
Read 2 more answers
An equilateral triangle has an altitude of 15 m. What is the perimeter of the triangle?
kondor19780726 [428]
Equilateral triangle mean every sides and angles are equal 
so the measure of angles is 60 degrees 
 given that has an altitude of 15 m so this mean that 

sin 60 = altitude / hypotenuse 

sqrt3 /2 = 15/hyp.

hyp. = 15/(sqrt3 /2)

hyp. = 30/sqrt3 = 30sqrt3 / 3 = 10sqrt3

so in this way ve got that a side length is equal 10sqrt3 and the perimeter 

P = 3*10sqrt3 

P = 30sqrt3 m  so the 3rd choice is right,correct sure 

hope helped 


3 0
3 years ago
Read 2 more answers
Help me do this please
wariber [46]

Answer:

58

Step-by-step explanation:

I think you add it when you add it you get 58. You add the angles

7 0
3 years ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
Mademuasel [1]

Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

\triangle PDC \sim \triangle PAB

Thus, By the definition of similarity,

\frac{PD}{PA} = \frac{DC}{AB}

\frac{PD}{PD+3} = \frac{11}{18} ( because PA = PD+DA)

⇒ 18 PD = 11 PD +33

⇒7PD = 33

⇒ PD = 33/7

Again by the definition of similarity,

\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


8 0
3 years ago
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