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3 years ago

Can you create electricity with magnetism?

2 answers:

7 0

Magnetic fields can be used to make electricity
The properties of magnets are used to make electricity. Moving magnetic fields pull and push electrons. ... Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current

victus00 [196]3 years ago

3 0

Answer:

Yes. That's how a magneto on a small lawn mower creates the spark for the spark plug. A magnet passes a coil and energizes the coil to produce electricity.

Step-by-step explanation:

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Im number 4 on daily rank brainliest so

Igoryamba

Answer:

Congrats!

Step-by-step explanation:

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3 years ago

Read 2 more answers

Heather traveled at a

larisa86 [58]

Answer:

54 miles

Step-by-step explanation:

divide 162/3.

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3 years ago

Triangle MNO is similar to triangle PRS. Find the measure of side PR. Round your

Fudgin [204]

Answer:

PR = 34.4

Step-by-step explanation:

x/54 = 7/11

11x = 378

x = 34.4

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3 years ago

6(a+3) = 18 + 6a

ivanzaharov [21]

6(a+3) = 18 + 6a 6(a+3)=6(3+a)
a+3=3+a
a-a=3-3
0a=0
<span>B. all real numbers</span>

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4 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

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4 years ago