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stellarik [79]
3 years ago
9

g The weight of a certain type of apple is normally distributed with a mean of 10.56 ounces and standard deviation of 0.9 ounces

. What is the first quartile, Q subscript 1, of the weight of this type of apple?
Mathematics
1 answer:
jeyben [28]3 years ago
6 0

Answer:

First Quartile Q1 = 9.9525

Step-by-step explanation:

For a standard normal distribution,

First quartile Q1 = μ - 0.675 σ

From the question mean μ = 10.56

Standard deviation σ = 0.9

Plugging these values into the first quartile equation, we have;

Q1 = 10.56 -0.675(0.9)

Q1 = 10.56 - 0.6075

Q1 = 9.9525

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I need some help on this. Not sure how to solve.
andreyandreev [35.5K]

Answer:

x = 9

Step-by-step explanation:

This shape is a 30-60-90 triangle, which means that the angles of the triangle are each 30°, 60° and 90°.  Given that the measures of the angles of the triangle are known, as well as one side, we can find the measures of all the other sides (example attached).  A 30-60-90 triangle is special because of the relationship of its sides.  The hypotenuse (directly across from the 90° angle) is equal to twice the length (2x) of the shorter leg, in this case labeled 'x' and directly across from the 30° angle.  The longer leg, across from the 60° angle, is equal to multiplying the shorter leg (x) by √3 or x√3.

Since the measure of the hypotenuse is given at 18, we can set the expression of that side equal to 18 and solve for x:

2x = 18  or x = 9


5 0
2 years ago
A graduated cylinder is filled with 20ml of water. Then, an 8g marble is dropped into the cylinder, causing the volume to change
Tema [17]

Answer:

The density of the marble is 2,000 kg/m³

Step-by-step explanation:

The given parameters for finding the density of the marble are;

The volume of water in the graduated cylinder, v₁ = 20 ml

The mass of the marble dropped into the graduated cylinder, m = 8 g

The new volume of the cylinder after the 8 g marble is dropped into the cylinder, v₂ = 24 ml

Therefore, the volume of the marble, v = v₂ - v₁

Substituting the known values gives;

The volume of the marble, v = 24 ml - 20 ml = 4 ml

Density, ρ = Mass, m/(Volume, v), the units of density is kg/m³

Therefore, the density of the marble, \rho _{marble}, is given as follows;

\rho _{marble} = m/v = (8 g)/(4 ml) = 2 g/ml

1 g/ml = 1 kg/l = 1,000 kg/m³

∴ \rho _{marble} = 2 kg/l = 2,000 kg/m³.

4 0
2 years ago
I need help with this
tankabanditka [31]
-2/2 and -2/-4 hoppeee it helps
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2 years ago
710,430 square feet of ground the arena covers 700,000 square feet of ground to what place value was the number rounded
vlada-n [284]
The hundred thousands ? :)
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3 years ago
Which concept is used to prove that the opposite sides of a parallelogram are congruent?
Neko [114]

Answer:

  congruent triangles

Step-by-step explanation:

You can eliminate useless answers based on their wording. "Similar" anything cannot be used to prove congruence. "Rectangles" will not help you prove congruence of parallelogram sides. The only reasonable choice is ...

  congruent triangles

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Typically, a diagonal is drawn through the figure, and the two triangles created are shown to be congruent, often by ASA. Then, by CPCTC, sides of the parallelogram are shown to be congruent.

7 0
2 years ago
Read 2 more answers
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