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stellarik [79]
3 years ago
9

g The weight of a certain type of apple is normally distributed with a mean of 10.56 ounces and standard deviation of 0.9 ounces

. What is the first quartile, Q subscript 1, of the weight of this type of apple?
Mathematics
1 answer:
jeyben [28]3 years ago
6 0

Answer:

First Quartile Q1 = 9.9525

Step-by-step explanation:

For a standard normal distribution,

First quartile Q1 = μ - 0.675 σ

From the question mean μ = 10.56

Standard deviation σ = 0.9

Plugging these values into the first quartile equation, we have;

Q1 = 10.56 -0.675(0.9)

Q1 = 10.56 - 0.6075

Q1 = 9.9525

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In the complex number system, which of the following is equal to
pogonyaev

Answer:

C) 122+154i

Step-by-step explanation:

(14-2i)(7+12i)\\\\(14)(7)+(14)(12i)+(-2i)(7)+(-2i)(12i)\\\\98+168i-14i-24i^2\\\\98+154i-24(-1)\\\\98+154i+24\\\\122+154i

Therefore, C is correct. Recall that i^2=-1

3 0
3 years ago
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Farmer tom has chickens and sheep he counts 48 heads and 134 legs how many sheep does he have
just olya [345]
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4 0
3 years ago
triangle LMN is similar to triangle FGH and LN/FH= 7/4. What is the ratio of the area of triangle LMN to the area of triangle FG
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Answer:

7

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

The x value has been translated by 2

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3 0
3 years ago
4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (
Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0
3 years ago
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