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tiny-mole [99]
2 years ago
10

There are 40 coins in a roll of nickles. Find the value of 25 rolls of nickels.

Mathematics
2 answers:
maksim [4K]2 years ago
3 0

To get the answer you have to multiply the number of coins per roll which is 40 by the number of rolls which is 25. So the equation you get is 40*25. And the answer you get is 1000

Troyanec [42]2 years ago
3 0

well, we know a nickel is 5 cents, a dollar is 100 cents, how many times does 5 go into 100?  100 ÷ 5 = 20, twenty times, so there are 20 nickels in 1 dollar.

these rolls each have 40 nickels though, namely 20 + 20 = 1 dollar + 1 dollar, so there are 2 dollars in one of these rolls.

we know there are 2 bucks in a roll of nickels, how many in 25 rolls?  25 * 2 = $50.

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What is the value of x in the equation 5(4x-10)+10x=4(2x-3)+2(x-4) ?
MrRissso [65]
5(4x - 10) + 10x = 4(2x - 3) + 2(x - 4)
20x - 50 + 10x = 8x - 12 + 2x - 8
30x - 50 = 10x - 20
30x - 10x = -20 + 50
20x = 30
x = 3/2 <==
6 0
3 years ago
Read 2 more answers
A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs
Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0
3 years ago
2,3,5,9,17,33 what are the next three terms?
stich3 [128]

The next three terms of sequence are 65, 129 and 257

<em><u>Solution:</u></em>

<em><u>Given sequence is:</u></em>

2, 3, 5, 9, 17, 33

We have to find the next three terms in sequence

<em><u>Let us find the logic used in this sequence</u></em>

2 + 2^0 = 2 + 1 = 3\\\\3 + 2^1 = 3 + 2 = 5\\\\5 + 2^2 = 5 + 4 = 9\\\\9 + 2^3 = 9 + 8 = 17\\\\17 + 2^4 = 17 + 16 = 33

Thus the sequence is increasing by 2 raised to power 0, 1, 2 and so on

<em><u>Thus the next three terms are found by:</u></em>

33 + 2^5 =33 + 32= 65\\\\65 + 2^6 = 65 + 64 = 129\\\\129 + 2^7 = 129 + 128 = 257

Thus the next three terms of sequence are 65, 129 and 257

3 0
2 years ago
Write 337,060 in expanded form using exponents
Agata [3.3K]

1. expand using place value.

337,060 = 300,000 + 30,000 + 7,000 + 000 + 60 + 0


Next, we will use exponents:

300,000 = 3 * 10^5

30,000 = 3 * 10^4

7,000 = 7 * 10^3

000 = 0 * 10^2

60 = 6 * 10

0 = 0 * 10^0


then after combing these exponents, we can write the number as:

337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 0 * 10^2 + 6 * 10 + 0 * 10^0


Finally, removing the meaningless zeroes, we would end up with:

337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 6 * 10


3 0
3 years ago
How do I write the sum of 6x and 2x is at least 39 ?
tatiyna
<h2>Put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .</h2>

Step-by-step explanation:

We have,,

6x and 2x

To find, the value of x = ?

According to question,

The sum of 6x and 2x is at least 39

∴ 6x + 2x = 39

⇒ 8x = 39

⇒  x = \dfrac{39}{8}

∴ The value of x = \dfrac{39}{8}

Thus, put x = \dfrac{39}{8} I write the sum of 6x and 2x is at least 39 .

5 0
2 years ago
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