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Andre45 [30]
3 years ago
8

Can someone please help with this.

Mathematics
2 answers:
wariber [46]3 years ago
6 0
The answer of this question would be B
Kaylis [27]3 years ago
4 0
A B and C is all true so I guess it’s not reversible?
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n the description of the following experiment, determine the experimental factor. A pharmaceutical company conducted an experime
arlik [135]

Answer:

Type of drink given to each group

Step-by-step explanation:

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2 years ago
Which equation represents a line that has a slope of 3/4 and passes through the point (2,1)?
ValentinkaMS [17]
The general equation of a line is:
\frac{y- y_{1}}{x- x_{1}} =m
When m is the gradient and x1 and y1 are the coordinates of the points on the line
Therefore:
\frac{y-1}{x-2}=3/4
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3 years ago
A distribution has the five-number summary shown below. What is the range of this distribution? 24, 36, 42, 57, 65
inn [45]
Hello!

To find the range of the distribution, we must order the data from least to greatest (it has already been done) and then subtract the smallest value from the largest value in the set.

In this set, the smallest value is 24, and the largest value is 65. Subtract:

65 - 24 = 41

A N S W E R:

The range of the distribution below is A. 41.
Have a wonderful day!
5 0
3 years ago
Read 2 more answers
Consider that the roots of a cubic equation with integral coefficients are 1, −2, and 3.
Iteru [2.4K]

Answer:

The answer is option A) X + 2

Step-by-step explanation:

Any polynomial of order n can be expressed in terms of their roots in factors of the form

(x-a)(x-b)(x-c)(x-d)....... = 0

Where a,b,c,d,... are the roots of the polynomial

In the example shown

(x+2) = (x-(-2))

And -2 happens to be the root of the polynomial in question

3 0
3 years ago
Read 2 more answers
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

6 0
3 years ago
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