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Licemer1 [7]
3 years ago
15

Gwen needs to add 2/3 of a cup of flour to a recipe. She only has a 1/3-cup measure. How many scoops of flour does Gwen need to

add?
Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0
She needs 2 scoops of flour
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(20 Points) Which test point holds true for 2/5x-1/5y≥0
valentinak56 [21]
Looking at the graph above, you are able to tell which points are true to the equation.

C. (5/2, 5) is true to the equation because it is located within the red region.

7 0
3 years ago
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Can someone help me with part B? Thank you! Brainliest for correct answer!
Ivanshal [37]

Answer: The mean is 5

Step-by-step explanation:

If you add all of the numbers and divide by how much numbers there are (8), then you get 5. Then the mean absolute deviation is the number away from the mean.

So I will put the mean absolute deviation in order of the numbers

4 (1 away from mean), 3 (2 away from the mean), 4( 1 away from the mean), 5 (same number as the mean), 6 (1 away from the mean), 6(1 away from mean), 8 (3 away from mean), and, finally another 4 (1 away)

Hope this helps :)

3 0
2 years ago
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Emily deposited $5,000 into a savings account 6 years ago. The simple interest rate is 3%. How much money did Emily earn in inte
Rainbow [258]

Answer:

$900

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 3%/100 = 0.03 per year,

then, solving our equation

I = 5000 × 0.03 × 6 = 900

I = $ 900.00

The simple interest accumulated

on a principal of $ 5,000.00

at a rate of 3% per year

for 6 years is $ 900.00.

6 0
3 years ago
What is the probability of choosing a face card that's also black from a deck of cards? Type your answer as a fraction
trasher [3.6K]

Answer:

6/52

Step-by-step explanation:

6 0
3 years ago
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the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


8 0
3 years ago
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