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Paraphin [41]
4 years ago
11

The question is below:

Mathematics
1 answer:
SSSSS [86.1K]4 years ago
5 0

Answer:

Triangles ABE and CDE are congruent by AAS.

Step-by-step explanation:

AB ≅ DC   (Opposite sides of a parallelogram are congruent.

m < AEB = m < DEC     (Vertical angles).

m < ABE = m < EDC     ( Alternate Interior angles).

So triangles  ABE and CDE are congruent by AAS.

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If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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