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Paraphin [41]
3 years ago
11

The question is below:

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

Triangles ABE and CDE are congruent by AAS.

Step-by-step explanation:

AB ≅ DC   (Opposite sides of a parallelogram are congruent.

m < AEB = m < DEC     (Vertical angles).

m < ABE = m < EDC     ( Alternate Interior angles).

So triangles  ABE and CDE are congruent by AAS.

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Determining whether an integer satisfies an inequality
Leto [7]
First we have - 6 < - 7 - 4x

Then we need to isolate the x of the inequality 4x < - 7 + 6

4x < - 1

x < - 1/4

The values less than - 1/4 are solutions for x

Btw if you need a tutor let me know:)
3 0
3 years ago
NEED HELP PLEASE FAST!
Aleks [24]
For one it would be c and d 
Two x is greater than seven 
three would be x is greater than or equal to 6 
Four would be subtract eight from both sides you get 24 and then divide by negative four which gets you negative six but then you have to turn the sign around. Number set would be anything above negative six,so like negative five, 52, and one
Five would be subtract 3 from both sides giving you 5 on the right side and then multiply by six on both sides giving you thirty on the right side, resulting in x is greater than or equal to thirty. Three numbers that would work would be thirty, fifty nine, and thirty five.
4 0
3 years ago
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
Completing the square: x^2+2x-7=8x
tia_tia [17]

Answer: x = 7, x = -1

Step-by-step explanation: Move the term to the left side

x^2 + 2x - 7 = 8x

x^2 + 2x - 7 - 8x = 0

Combine like terms

x^2 + 2x - 7 - 8x = 0

x^2 - 6x - 7 = 0

x^2 - 6x - 7 = 0

a = 1

b = -6

c = -7

x = -(-6) + (-6)^2 - 4 x 1(-7)/ 2 x 1

Evaulate the Exponent

Multiply the numbers

Add the numbers

Evaluate the square root

Multiply the numbers x = 6 ± 8/2

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

x = 6 + 8/2

x = 6 - 8/2

Rearrange and isolate the variable to find each solution

x = 7

x = -1

4 0
2 years ago
1 As a part of her project, Flora made a scale drawing of the zoo with a scale factor of
Aneli [31]

Answer:

honestly I have no idea

Step-by-step explanation:

1x-3x=2x

7 0
3 years ago
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