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anastassius [24]
3 years ago
15

Looking for some assistance with a Finance question.

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0
I am here , please ask your question.

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Explain the following in complete sentences:
Soloha48 [4]

Answer:

The answer is that they are both paralleagrams.

Step-by-step explanation:

Hope this helps

8 0
3 years ago
Which set of side lengths forms a right triangle?
Valentin [98]
15, 36, and 39 ‎ ‎ ‎ ‎
5 0
2 years ago
The probability that a visitor to an animal shelter will adopt a dog is .20. out of nine visits, what is the probability that at
lana66690 [7]
This is a binomial probability situation, since a dog either is adopted or is not adopted.  The chances of a dog's being adopted in 0.20.  Here we're speaking of 9 visits.  Thus, n=9, p=0.20.

One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs.  Add together these nine probabilities to get your answer.

But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.

Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134.  Subtracting this from 1.000, we get 0.866 (answer to this problem).
8 0
3 years ago
a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance re
s344n2d4d5 [400]

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

5 0
2 years ago
assume that the number of production defects is 28 and that 14 of these are classified as major defects, 8 are classified as des
Arlecino [84]

Answer:  5

Step-by-step explanation:

Let A denotes the number of major defects and B denotes the number of design defect.

By considering the given information, we have

U=28\ ;\ n(A)=14\ ;\ n(B)=8\ \ ;\ n(A^c\cap B^c)=1

Now, the number of major defects or design defects:

n(A\cup B)=U-n(A^c\cap B^c)=28-11=17

Also,

n(A\cap B)=n(A)+n(B)-n(A\cup B)\\\\\Rightarrow\ n(A\cap B)=14+8-17=5

Hence, the number of  design defects were major=5

6 0
3 years ago
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